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3 years ago

_____ can be reduced but it cannot be eliminated.

2 answers:

3 0

Heat can be reduced but it cannot be eliminated completely there is some amount if heat energy present even if it is absolute zero(-273degrees Celsius)

Grace [21]3 years ago

3 0

Answer:

I am pretty sure its friction

Explanation: Because it is the only thing stopping us freom sliding around the earth.

You might be interested in

A weight lifter applies an upward force of 1100 N while lowering a dumbbell

Paul [167]

Answer:

Explanation:

$work = force \times distance$

$work = 1100 \times 0.5$

$= 550 \: j$

hope it helped a lot

pls mark brainliest with due respect .

6 0

2 years ago

What will happen if more solute is added than can be dissolved .

zysi [14]

The solute would then sink to the bottom and would not dissolve

3 0

3 years ago

Is the energy of a wave is calculated by squaring the frequency of the wave?

Misha Larkins [42]

Nope.
Energy is directly proportional to frequency. and when you calculate energy, you multiply frequency with a constant number called "Planck's Constant"

E = hf

Hope this helps!

5 0

3 years ago

A steel spur pinion has a module of 2 mm, 17 teeth cut on the 20° full-depth system, and a face width of 20 mm. At a speed of 16

erastovalidia [21]

Answer:

The value of bending stress on the pinion 35.38 M pa

Explanation:

Given data

m = 2 mm

Pressure angle $\phi$ = 20°

No. of teeth T = 17

Face width (b) = 20 mm

Speed N = 1650 rpm

Power = 1200 W

Diameter of the pinion gear

D = m T

D = 2 × 17

D = 34 mm

Velocity of the pinion gear

$V =\pi D( \frac{N}{60} )$

$V = 3.14 (0.034) \frac{(1650)}{60}$

$V = 2.93 \frac{m}{s}$

Form factor for the pinion gear is

Y = 0.303

Now

$K_{v} = \frac{6.1 +0.303}{6.1} = 1.049$

Force on gear tooth

$F = \frac{P}{V}$

$F = \frac{1200}{2.93}$

F = 408.73 N

Now the bending stress is given by the formula

$\sigma = \frac{K_{v} F}{m b y}$

$\sigma = \frac{(1.049)(408.73)}{(0.002)(0.02)(0.303)}$

$\sigma$ = 35.38 M pa

This is the value of bending stress on the pinion

8 0

3 years ago

How far from the base of the platform does she land?

seropon [69]

When Janet leaves the platform, she's moving horizontally at 1.92 m/s. We assume that there's no air resistance, and gravity has no effect on horizontal motion. There's no horizontal force acting on Janet to make her move horizontally any faster or slower than 1.92 m/s.

She's in the air for 1.1 second before she hits the water.

Moving horizontally at 1.92 m/s for 1.1 second, she sails out away from the platform

(1.92 m/s) x (1.1 sec) = <em>2.112 meters</em>

3 0

3 years ago