The accuracy is associated with magnitude of fractional error or relative error in that measurement
the precision of a measurement is associated with least count of the measuring instrument.
precision does not mean accuracy but both are highly demanded while making measurements in physics.
In the compound iodine heptafluoride: (hints: write out the molecular formula of this compound before answering the question. Also be sure you clearly understand the concepts of charge, oxidation numbers, how to determine charge and oxidation numbers, and - most important of all! - the similarities and the differences between charges and oxidation numbers)
<u>Each fluorine atom has a charge of 1</u>
<h3>What is
iodine heptafluoride?</h3>
The interhalogen compound iodine heptafluoride, often known as iodine(VII) fluoride or iodine fluoride, has the chemical formula IF7. As anticipated by VSEPR theory, it exhibits a unique pentagonal bipyramidal structure. The molecule is capable of undergoing the Bartell process, a pseudorotational rearrangement that is similar to the Berry mechanism but for a heptacoordinated system. It produces colorless crystals that melt at 4.5 °C and have a very narrow liquid range with a boiling point of 4.77 °C. The dense mist has an unpleasant, musty smell. The molecule is symmetrical with D5h. suggestion
To learn more about iodine heptafluoride from the given link:
brainly.com/question/28200374
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Answer:
The bee's energy output can be calculated directly, and related to its size. it only needs enough air resistance to counter its weight and enough power in its wings to sustain this resistance. it bee like that.
Answer:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.03901 mol/liter
- [Cl₂O] = 0.02351 mol/liter
Explanation:
<u />
<u>1. Chemical reaction:</u>

<u>2. Initial concentrations:</u>
i) 1.3 g H₂O
- Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol
- Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter
ii) 2.2 g Cl₂O
- Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol
- Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter
<u>3. ICE (Initial, Change, Equilibrium) table</u>

I 0.0481 0.0326 0
C -x -x +x
E 0.0481-x 0.0326-x x
<u />
<u>4. Equilibrium expression</u>
![K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}](https://tex.z-dn.net/?f=K_c%3D%5Cdfrac%7B%5BHOCl%5D%5E2%7D%7B%5BH_2O%5D.%5BCl_2O%5D%7D)

<u />
<u>5. Solve:</u>

Use the quadatic formula:

The positive result is x = 0.00909
Thus the concentrations are:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter
- [Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter