Answer:
1) Ethane is the limiting reactant
2) mass of CO₂ produced is 733.33 g
Explanation:
C₂H₆ + 2O₂ → 2CO₂ + 3H₂ ------------------------(1)
molar ratio for equation (1) can be shown as;
1 : 2 → 2 : 3
molecular weight of moles of C₂H₆ = 30 g/mol
molecular weight of moles of O₂ = 32 g/mol
molecular weight of moles of CO₂ = 44 g/mol
mass of O₂ = 220 g
mass of C₂H₆ = 250 g
number of moles of O₂ = mass ÷ molecular weight = 220 g ÷ 32 g/mol * 2 = 13.75 moles
number of moles of C₂H₆ = mass ÷ molecular weight = 250 g ÷ 30 g/mol = 8.333 moles
1) Ethane is the limiting reactant as the 8.333 moles will finish before the 13.75 moles of the oxygen is totally consumed.
2) 1 mole of C₂H₆ will form 2 moles of CO₂
Therefore, 8.333 moles will form 16.667 moles of CO₂
mass of CO₂ formed = number of moles * molecular weight = 16.667 * 44 = 733.33 g
Answer:
71.372 g or 0.7 moles
Explanation:
We are given;
- Moles of Aluminium is 1.40 mol
- Moles of Oxygen 1.35 mol
We are required to determine the theoretical yield of Aluminium oxide
The equation for the reaction between Aluminium and Oxygen is given by;
4Al(s) + 3O₂(g) → 2Al₂O₃(s)
From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.
Therefore;
1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen
1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium
Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.
4 moles of aluminium reacts to generate 2 moles aluminium oxide.
Therefore;
Mole ratio Al : Al₂O₃ is 4 : 2
Thus;
Moles of Al₂O₃ = Moles of Al × 0.5
= 1.4 moles × 0.5
= 0.7 moles
But; 1 mole of Al₂O₃ = 101.96 g/mol
Thus;
Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol
= 71.372 g
Answer:
Explanation:
Q = m × Cp × delta T
Where,
Q is the heat gained by water
m is the mass of water
Cp = specific heat capacity of water
= 4.18 kJ per kilogram per degree Celsius (J/kg°C).
This means that it takes 4,180 J to raise the temperature of 1 kg of water by 1°C
delta T is the difference in temperature
A.
The smaller beaker had a bigger temperature rise because the same energy has been given to a smaller number of water particles in the beaker than those particles in the large beaker so each particle is moving faster than those in the other beaker.
B.
Since both beakers were heated at the same time, they both gain the same amount of energy.
Qlarge = Qsmall
Answer:
This question is incomplete and unclear; the complete question including the missing part is:
Emelie is working on a science project. Her task is to answer the question:
"Does Rogooti (a hair cream sold on TV) affect the speed of hair growth
(in length)". Her family is willing to volunteer for the experiment. Identify the control group (CG) and the independent and dependent variables.
ANSWER:
Independent variable: Rogooti hair cream
Dependent variable: Speed of hair growth/length
Control group: Family members that do not use the Rogooti hair cream
Explanation:
In an experiment, the independent variable is the variable that the experimenter changes or manipulates in order to bring about a measurable response. In this case, the ROGOOTI HAIR CREAM is the independent variable.
Dependent variable refers to the variable that is measured or the variable that responds to the change made to the independent variable. In this case, the dependent variable is SPEED AT WHICH HAIR GROWS (IN LENGTH).
Control group in an experiment is the group that does not receive the experimental treatment. In this case, the experimental treatment is the Rogooti hair cream, hence, the control group will be the VOLUNTEER FAMILY MEMBERS THAT DOES NOT RECEIVE THE ROGOOTI HAIR CREAM ON THEIR HAIR.
Answer:
21
Explanation:
Formula;
Mass number = number of protons + number of neutrons
= 9 + 12
= 21