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3 years ago

14

Henry was given this cool toy for his birthday, he can use it to tell how fast someone is moving at that moment in time. The toy

must calculate the person's

1 answer:

Jobisdone [24]3 years ago

6 0

Speed, the toy can calculate a persons speed

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How can i prove the conservation of mechanical energy?

FinnZ [79.3K]

Answer:

We can also prove the conservation of mechanical energy of a freely falling body by the work-energy theorem, which states that change in kinetic energy of a body is equal to work done on it. i.e. W=ΔK. And ΔE=ΔK+ΔU. Hence the mechanical energy of the body is conserved

Explanation:

5 0

3 years ago

One of the harmonics on a string 1.30m long has a frequency of 15.60 Hz. The next higher harmonic has a frequency of 23.40 Hz. F

Alja [10]

Answer:

$\large \boxed{\text{(a) 7.800 Hz; (b) 20.3 m/s; 40.6 m/s; 60.8 m/s}}$

Explanation:

a) Fundamental frequency

A harmonic is an integral multiple of the fundamental frequency.

$\dfrac{\text{23.40 Hz}}{\text{15.60 Hz}} = \dfrac{1.500}{1} \approx \dfrac{3}{2}$

$f = \dfrac{\text{24.30 Hz}}{3} = \textbf{7.800 Hz}$

b) Wave speed

(i) Calculate the wavelength

In a fundamental vibration, the length of the string is half the wavelength.

$\begin{array}{rcl}L & = & \dfrac{\lambda}{2}\\\\\text{1.30 m} & = & \dfrac{\lambda}{2}\\\\\lambda & = & \text{2.60 m}\\\end{array}$

(b) Calculate the speed s

$\begin{array}{rcl}v_{1}& = & f_{1}\lambda\\& = & \text{7.800 s}^{-1} \times \text{2.60 m}\\& = & \textbf{20.3 m/s}\\\end{array}$

$\begin{array}{rcl}v_{2}& = & f_{2}\lambda\\& = & \text{15.60 s}^{-1} \times \text{2.60 m}\\& = & \textbf{40.6 m/s}\\\end{array}$

$\begin{array}{rcl}v_{3}& = & f_{3}\lambda\\& = & \text{23.40 s}^{-1} \times \text{2.60 m}\\& = & \textbf{60.8 m/s}\\\end{array}$

4 0

3 years ago

Please help on this one?

diamong [38]

Answer:

ITS C

Explanation:

7 0

3 years ago

Question 1 (1 point)

Juli2301 [7.4K]

Hello!

$\large\boxed{800Ns}$

Remember that impulse is equivalent to:

Impulse = force (N) × time (s)

Plug in the given force and time:

Impulse = 25 × 32

Impulse = 800 Ns

3 0

2 years ago

if a sports car can go from 0 to 60 mph in 3.8 seconds, what would be it's final speed after 6 seconds if it's starting speed wa

erma4kov [3.2K]

Verrrrrry interesting !

Acceleration = (change in speed) / (time for the change)

The car's acceleration is (60 mph) / (3.8 sec) = (60/3.8) mile/hr-sec .

Final speed = (original speed) + (acceleration · time)

   = (30 mi/hr) + (60/3.8 mi/hr-sec)·(6 sec)

   = (30)mi/hr + (360 / 3.8)mi/hr

   = 124.7 mph .

4 0

3 years ago