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Nata [24]
4 years ago
10

Compare and contrast these isotopes: uranium -239, uranium -238, and uranium -235

Chemistry
2 answers:
kykrilka [37]4 years ago
4 0
They all have the same number of protons and electrons but differ in the number of neutrons because they are isotopes.
PSYCHO15rus [73]4 years ago
3 0

<u>Answer:</u> They have same number of protons but differ in number of neutrons.

<u>Explanation:</u>

Isotopes are defined as the species which have same number of neutrons but differ in the number of neutrons.

Uranium is the 92nd element of the periodic table.

Atomic number is defined as the number of protons that are present in an atom.  

Atomic number = Number of protons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

For the given isotopes:  _{92}^{239}\textrm{U},_{92}^{238}\textrm{U}\text{ and }_{92}^{235}\textrm{U}

  • For _{92}^{239}\textrm{U}

Number of protons = 92

Number of neutrons = 239 - 92 = 147

  • For _{92}^{238}\textrm{U}

Number of protons = 92

Number of neutrons = 238 - 92 = 146

  • For _{92}^{235}\textrm{U}

Number of protons = 92

Number of neutrons = 235 - 92 = 143

Hence, they have same number of protons but differ in number of neutrons.

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If 11.7 g of aluminum reacts with 37.2 g of copper (II) sulfate according to the following reaction, how many grams of aluminum
zhannawk [14.2K]

Answer:

There is 26.59 grams of aluminium sulfate produced

Explanation:

<u>Step 1:</u> Data given

Mass of aluminium = 11.7 grams

Mass of copper (II) sulfate = 37.2 grams

Molar mass of Aluminium = 26.98 g/mol

Molar mass of CuSO4 = 159.61 g/mol

Molar mass of Al2(SO4)3 = 342.15 g/mol

<u />

<u>Step 2</u>: The balanced equation

2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

<u>Step 3</u>: Calculate moles of Aluminium

Moles Al = mass Al / molar mass Al

Moles Al = 11.7 grams / 26.98 g/mol

Moles Al = 0.434 mol

<u>Step 4</u>: Calculate moles of CuSO4

Moles CuSO4 = 37.2 grams / 159.61 g/mol

Moles CuSO4 = 0.233 moles

<u>Step 5:</u> Calculate limiting reactant

For 2 moles of Al we need 3 moles of CuSO4

CuSO4 is the limiting reactant. It will be completely consumed (0.233 moles).

Al is in excess. There will be consumed 0.233 *(2/3) = 0.1553 moles

There will remain 0.434 - 0.1553 = 0.2787 moles

<u>Step 6: </u>Calculate moles of Al2(SO4)3

For 2 moles of Al we need 3 moles of CuSO4, to produce 1 mole of Al2(SO4)3 and  3 moles of Cu

For 0.233 moles CuSO4 we produce 0.233/3 = 0.0777 moles of Al2(SO4)3

<u>Step 7</u>: Calculate mass of Al2(SO4)3

Mass of Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3

Mass of Al2(SO4)3 = 0.0777 moles * 342.15g/mol

Mass of Al2(SO4)3 = 26.59 grams

There is 26.59 grams of aluminium sulfate produced

4 0
3 years ago
Why science can answer some questions, but not others
Makovka662 [10]
Cause its not all about science
5 0
3 years ago
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Cuales son todas las propiedades periodicas
Naily [24]

Answer: chicken nugget

Explanation:

3 0
3 years ago
What is the noble gas configuration for zirconium?
Mkey [24]

Answer:

[Kr] 4d² 5s²

Explanation:

5 0
3 years ago
How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution?
Rufina [12.5K]

Answer : The number of moles of Ba(NO_3)_2 are 0.50 moles.

Solution : Given,

Volume solution = 0.25 L

Molarity of solution = 2.00 mole/L

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

Molarity=\frac{\text{ Number of moles of solute}}{\text{ Volume of solution}}

Now put all the given values in this formula, we get number of moles.

2.00mole/L=\frac{\text{ number of moles of }Ba(NO_3)_2}{0.25L}

By rearranging the term,

Number of moles of Ba(NO_3)_2 = 0.50 moles

Therefore, 0.50 moles of Ba(NO_3)_2 are there in the solution.


4 0
4 years ago
Read 2 more answers
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