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4 years ago

What happens when the electron moves from the first energy level to the second energy level?

2 answers:

8 0

Energy is absorbed by the atom.

Emission lines occur only in the case of transitions from higher to lower energy levels in which energy is emitted.

natali 33 [55]4 years ago

5 0

Answer:

energry is absorbed by the atom

Explanation:

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3 years ago

Specialized intermodal tank container which carries refrigerated liquid gases, oxygen, or helium

Nookie1986 [14]

This would be a cryogenic intermodal tank. These are used to store and transport HAZMAT gases that require storage under specific pressure and temperature parameters. Cryogenic Intermodal tanks have pressure of 25 Psi or less.

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3 years ago

Where do organisms obtain the energy they need

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autotrophs and heterotrophs. Autotrophs (producers) use energy directly from the sun or from chemicals to produce organic molecules. Photoautotrophs such as plants use energy from sunlight to make organic compounds by photosynthesis.

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3 years ago

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What are the full forms of RADAR and SONAR

Stels [109]

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RADAR and SONAR. Although they rely on two fundamentally different types of wave transmission, Radio Detection and Ranging (RADAR) and Sound Navigation and Ranging (SONAR) both are remote sensing systems with important military, scientific and commercial applications

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4 years ago

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Find the area of the surface.the part of the plane x 2y 3z = 1 that lies inside the cylinder x2 y2 = 6

AlladinOne [14]

I assume you mean the plane $x+2y+3z=1$ . Its area over the region

$R = \left\{(x,y) ~:~ x^2 + y^2 \le 6\right\}$

is given by the integral

$\displaystyle \iint_R dA = \iint_R \sqrt{1 + \left(\frac{\partial f}{\partial x}\right)^2 + \left(\frac{\partial f}{\partial y}\right)^2} \, dx \, dy$

where $z=f(x,y) = \frac{1 - x - 2y}3$ .

We have

$\dfrac{\partial f}{\partial x} = -\dfrac13$

$\dfrac{\partial f}{\partial y} = -\dfrac23$

so that the area element is

$dA = \sqrt{1 + \left(-\dfrac13\right)^2 + \left(-\dfrac23\right)^2} \,dx\,dy = \dfrac{\sqrt{14}}3\,dx\,dy$

Then we have

$\displaystyle \iint_R dA = \frac{\sqrt{14}}3 \iint_R dx \, dy$

and the remaining integral is exactly the area of the disk $x^2+y^2\le6$ . Its radius is √6, so its area is π (√6)² = 6π. So the area of the surface is

$\displaystyle \iint_R dA = \frac{\sqrt{14}}3 \cdot 6\pi = \boxed{2\sqrt{14}\pi}$

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2 years ago