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Nadya [2.5K]
3 years ago
5

Which of the following compounds is an Arrhenius base? Which of the following compounds is an Arrhenius base?

Chemistry
2 answers:
Eddi Din [679]3 years ago
5 0
A). CH3OH I think !!!!!!!!
Naya [18.7K]3 years ago
5 0

Explanation:

Arrhenius base are defined as the specie which when dissolved in water dissociate to give hydroxide ions.

For example, Sr(OH)_{2} being an ionic compound when dissolved in water will give Sr^{2+} and OH^{-} ions.

Whereas alcohol is neutral in water under normal conditions. Hence, CH_{3}OH will not dissociate to give hydroxide ions.

On the other hand, Arrhenius acids are the species which when dissolved in water will dissociate to give hydrogen ions.

For example, CH_{3}COOH and HClO will give hydrogen ions when dissolved in water.

Thus, we can conclude that out of the given options Sr(OH)_{2} is an Arrhenius base.

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Strontium is a soluble earth metal with the nuclear number 38. Phosphate is a polyatomic particle containing phosphorus and oxygen molecules. Strontium loses electrons to turn out to be emphatically charged, and phosphate is an adversely charged particle.

Explanation:

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How are cells the basic units to all organisms??
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Cells as Building Blocks

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2 years ago
What is the key element fountain all carbohydrates lipids proteins and nucleus acid
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6 0
3 years ago
A substance is composed of only one kind of Adam and can't be separated into simpler substances are converted into it another su
Zarrin [17]

Answer:

Element

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3 0
2 years ago
A single hydrogen atom has a mass of 1.67 × 10−24 g. A sodium atom has an atomic mass of 23. How many sodium atoms are required
statuscvo [17]
<h3>Answer:</h3>

                      2.55 × 10²² Na Atoms

<h3>Solution:</h3>

Data Given:

                 M.Mass of Na  =   23 g.mol⁻¹

                 Mass of Na  =  973 mg  =  0.973 g

                 # of Na Atoms  =  ??

Step 1: Calculate Moles of Na as:

               Moles  =  Mass ÷ M.Mass

               Moles  =  0.973 g ÷ 23 g.mol⁻¹

               Moles  =  0.0423 mol

Step 2: Calculate No, of Na Atoms as:

As 1 mole of sodium atoms counts 6.022 × 10²³ and equals exactly to the mass of 23 g. So, we can write,

               Moles  =  No. of Na Atoms ÷ 6.022 × 10²³ Na Atoms.mol⁻¹

Solving for No. of Na Atoms,

               No. of Na Atoms  =   Moles × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =   0.0423 mol × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =  2.55 × 10²² Na Atoms

<h3>Conclusion: </h3>

                          2.55 × 10²² sodium atoms are required to reach a total mass of 973 mg in a substance of pure sodium.


5 0
3 years ago
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