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Neporo4naja [7]
4 years ago
12

Why do stars have names

Physics
1 answer:
zmey [24]4 years ago
7 0

Astronomers give stars names so that they're able to identify and keep track of them more easily.

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What is the purpose of the material surrounding the metal inside the lamp cord?
Tamiku [17]
The prongs on the plug and the wire inside<span> the </span>cord<span> are </span>metal<span> but they are </span>surrounded<span> by plastic or rubber insulation so you do not get shocked when you touch the </span>cord
5 0
4 years ago
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Compare an earthquake with a Richter scale magnitude of 5.5 to one with a magnitude of 7.5.
maksim [4K]
The 7.5 is a 100 times stronger than the 5.5 . The 100 comes from the increase in scale from 5.5 to 7.5 which is an increase of two so you multiply the strength of the weaker earthquake 10^7-5=10^2=100 and that gives you the strength of the stronger earthquake!
7 0
3 years ago
An 30-turn coil has square loops measuring 0.341 m along a side and a resistance of 3.61 Ω. It is placed in a magnetic field tha
Verdich [7]

Answer:

Thus, the induced current in the coil at t =1.73s is 9.98 A.

Explanation:

Faraday's law says

$\varepsilon = N \frac{d \Phi_B}{dt} $

where N is the number of turns and \Phi_B is the magnetic flux through the square coil:

Now,

N = 30

\theta = 37.5^o

A = (0.341m)^2= 0.11623m^2

B = 1.45t^3;

therefore,

$\varepsilon = N \frac{d \Phi_B}{dt}  = N\frac{d ( BA\:cos(\theta))}{dt}  = 30*\frac{d ( (1.45t^2)(0.1163)\:cos(37.5^o))}{dt}$

=30*(0.1163)\:cos(37.5^o)*1.45*\dfrac{d ( t^3)}{dt}  = 12.04t^2

\boxed{\varepsilon = 12.04t^2}

is the emf induced in the coil.

Now, the loop is connected to R = 3.61\Omega resistance; therefore, at t = 1.73s

\varepsilon = RI = 12.04t^2

RI = 12.04(1.73)^2

RI = 36.03

I = \dfrac{36.03}{3.61\Omega }

\boxed{I = 9.98A }

Thus, the current in the coil at t =1.73s is 9.98 A.

8 0
4 years ago
In a nuclear fusion reaction, atoms:<br> split apart.<br> combine.<br> explode.<br> cool down.
Sergeeva-Olga [200]
The answer is combine
5 0
3 years ago
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PLEASE HELP HURRY!!
kenny6666 [7]

You don't need both. GPE is the gravitational potential energy caused by the fact that an object is not touching the ground of the earth. KE is caused by an object moving. This problem says that the bowling ball "sits" meaning that you only need the GPE because it's not moving and it is not touching the surface. You would use the GPE equation to find how much Potential energy an object has. If you want its velocity,  you would set the answer to the GPE equation equal to the KE equation to find its velocity.

8 0
4 years ago
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