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exis [7]
3 years ago
15

A 7.5 cm object is 14 cm from a concave lens, which has a focal length of –7 cm. Its image is 5 cm in front of the lens. What is

the height of the image?
Round your answer to the nearest whole number.

A. –3 cm

B. 3 cm

C. 21 cm
Physics
2 answers:
Tomtit [17]3 years ago
6 0

Answer:

The answer is 3 cm

Explanation:

Rama09 [41]3 years ago
3 0
Given conditions:
height of object = 7.5cmdistance of object from mirror  = 14 cmfocus length = -7 cmimage distance =  ?
Using mirror formula: 
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)


Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)
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Answer:

I=3.348Kgm^2

Explanation:

From the question we are told that:

Mass m=14.8kg

Radiusr=0.752m

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I=\frac{2}{5}14.8*(0.752)^2

I=3.348Kgm^2

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Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

\sf \: F=ma

Where,

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In our case,

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Answer:

31.25 m

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Explanation:

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V = 0 (in going up)

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