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exis [7]
3 years ago
15

A 7.5 cm object is 14 cm from a concave lens, which has a focal length of –7 cm. Its image is 5 cm in front of the lens. What is

the height of the image?
Round your answer to the nearest whole number.

A. –3 cm

B. 3 cm

C. 21 cm
Physics
2 answers:
Tomtit [17]3 years ago
6 0

Answer:

The answer is 3 cm

Explanation:

Rama09 [41]3 years ago
3 0
Given conditions:
height of object = 7.5cmdistance of object from mirror  = 14 cmfocus length = -7 cmimage distance =  ?
Using mirror formula: 
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)


Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)
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Explanation:

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Two carts are free to slide along the frictionless track shown in figure below. Cart A of mass m1 = 8 kg is released from 12m. A
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The height reached by the two carts after collision is determined as 5.34 m.

<h3>Initial velocity of Cart A</h3>

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v = √(2 x 9.8 x 12)

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<h3>Final velocity of the two carts after the collision</h3>

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122.72 = 12v

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TiliK225 [7]

Answer:

E = 6.77 *10^{3} N/C

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shepuryov [24]

Answer:

Less impact???

Explanation:

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Answer:

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