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3 years ago

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Lab: Magnetic and Electric Fields lab report. Edge 2020

1 answer:

Lubov Fominskaja [6]3 years ago

3 0

Answer:

what is the question

Explanation: plz give the brainliest

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18°C = _____ <br> A -255 K<br> B- 0 K<br> C- 18 K<br> D- 291 K

mariarad [96]

Answer:

291 K is the answer

Explanation:

to get Kelvin from Celsius use the following

Kelvin = Celsius +273

= 18 +273

= 291

7 0

2 years ago

At what angle two forces P + Q and (P - Q) act so that their resultant is :

stiv31 [10]

Use resultant formula

$\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\theta}}$

So

#1

A be p+q and B be p-q

$\\ \rm\Rrightarrow R=\sqrt{3p^2+q^2}$

$\\ \rm\Rrightarrow \sqrt{(p+q)^2+(p-q)^2+2(p+q)(p-q)cos\alpha}=\sqrt{3p^2+q^2}$

$\\ \rm\Rrightarrow 2p^2+2q^2+2(p^2-q^2)cos\alpha=3p^2+q^2$

$\\ \rm\Rrightarrow 2cos\alpha=1$

$\\ \rm\Rrightarrow cos\alpha=\dfrac{1}{2}$

$\\ \rm\Rrightarrow \alpha=\dfrac{\pi}{3}$

#2

$\\ \rm\Rrightarrow 2(p^2+q^2)+2(p^2-q^2)cos\beta=2(p^2+q^2)$

$\\ \rm\Rrightarrow 2cos\beta=0$

$\\ \rm\Rrightarrow cos\beta=0$

$\\ \rm\Rrightarrow \beta=\dfrac{\pi}{2}$

#3

$\\ \rm\Rrightarrow 2(p^2+q^2)+2(p^2-q^2)cos\gamma=p^2+q^2$

$\\ \rm\Rrightarrow 2(p^2-q^2)cos\gamma=-(p^2+q^2)$

$\\ \rm\Rrightarrow cos\gamma =\dfrac{q^2-p^2}{2(p^2-q^2)}$

$\\ \rm\Rrightarrow \gamma=cos^{-1}\left(\dfrac{q^2-p^2}{2(p^2+q^2)}\right)$

8 0

2 years ago

Read 2 more answers

The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational

zzz [600]

Answer:

$P=3.61\times 10^{-3}\ Pa$

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

$P=\dfrac{F}{A}$

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

$P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa$

So, the maximum pressure created by brick is $3.61\times 10^{-3}\ Pa$ .

5 0

3 years ago

What is the ratio of the sun’s gravitational pull on Mercury to the sun’s gravitational pull on the earth?

Marta_Voda [28]

Answer:

The answer is $\frac{F_{Sun-Mercury} }{F_{Sun-Earth} } =0,3709$ . Let's learn why.

Explanation:

Newton's law of universal gravitation says;

$F_{g} =G.\frac{m_{1}.m_{2}}{r^{2}}$

Here G is a universal gravitational <u>constant</u> and is measured experimentally.

Sun's gravitational pull on mercury is:

$F_{Sun-Mercury} =G.\frac{m_{sun}.3,30.10^{23}}{(5,79.10^{10})^{2} }$

Therefore $F_{Sun-Mercury} = Gm_{sun} 98,4366$

Sun's gravitational pull on Earth is:

$F_{Sun-Earth} =G.\frac{m_{sun} 5,97.10^{24} }{(1,50.10^{11}) ^{2}}$

Therefore $F_{Sun-Earth} =Gm_{sun} 265,33$

As a result;

$\frac{F_{Sun-Mercury}}{F_{Sun-Earth} }=\frac{Gm_{sun}98,4366}{Gm_{sun}265,33 } =0,3709$

4 0

3 years ago

A wind generator, such as the one shown , uses the power of wind to generate electricity What do you think is happening inside t

sesenic [268]

Answer:

A wind turbine captures the wind, which then produces a renewable energy source. The wind makes the rotor spin; as the rotor spins, the movement of the blades drives a generator that creates energy. The motion of the blades turning is kinetic energy. It is this power that we convert into electricity.

8 0

3 years ago

Read 2 more answers