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Korolek [52]
4 years ago
13

Sometime around 2024, astronomers at the European Southern Observatory hope to begin using the E-ELT (European Extremely Large T

elescope), which is planned to have a primary mirror 42 m in diameter. Let us assume that the light it focuses has a wavelength of 550 nm. (a) What is the most distant Jupiter-sized planet the telescope could resolve, assuming its resolution is limited only by diffraction? Express your answer in meters and light years. (b) The nearest known exoplanets (planets beyond the solar system) are around 20 light years away. What would have to be the minimum diameter of an optical telescope to resolve a Jupiter-sized planet at that distance using light of wavelength 550 nm? ( 1 light year = 9.461 × 10 15 m )

Physics
1 answer:
soldier1979 [14.2K]4 years ago
5 0

Answer:

Expression for angular resolution is;

θ = 1.22π/d

a) 0.85 light year

b) 2.15 x 10³ m

Explanation:

See attached images

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Answer:

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Explanation:

Let Fb be Force of block and thus;

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Now, the question says this force Fb rests at an inclined plane [email protected] 30° angle

Thus;

Force parallel to inclined plane = 88.29 x sin30° = 44.145 N.

Force perpendicular to the inclined plane = 88.29 x cos30 = 76.46 N

Now, when an object is falling freely, we know that

h = (1/2)at^(2)

From the question, the height is 5m and t= 2 seconds

Thus;

5 = (1/2)a(2)^(2)

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Now, in inclined planes, perpendicular force - kinetic friction force = Resultant force

Thus let perpendicular be Fp and kinetic friction force be Fk and so;

Fp - Fk = F

F= ma = 9 x 2.5 = 22.5N

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Thus, Fk = 44.145 - 22.5 = 21.645N

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