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3 years ago

What is the sequence of energy transformations when electricity is generated from fossil fuels?

Physics

2 answers:

kow [346]3 years ago

7 0

B) is the answer, hope it helps

hodyreva [135]3 years ago

3 0

B. Chemical energy stored in the fuel, thermal energy when it is burned, mechanical energy as a sort of intermediate to turn it into electrical energy.

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What happens to an object after being transported to three planets in the solar system?

alukav5142 [94]

The weight changes but the mass will stay the same.

6 0

3 years ago

A 57 kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.1 m/s. The acceleration of

kari74 [83]

Answer:

Her altitude as she crosses the bar, h₂ is approximately 6.1 m

Explanation:

The given parameters of the motion of the pole vaulter are;

The mass of the pole vaulter, m = 57 kg

The speed with which the pole vaulter is running, u = 11 m/s

The speed of the pole vaulter when she crosses the bar, v = 1.1 m/s

The acceleration due to gravity, g = 9.8 m/s²

From the total mechanical energy, M.E. equation, we have;

M.E. = P.E. + K.E.

Where;

P.E. = The potential energy of the motion = m·g·h

K.E. = The kinetic energy of the motion = 1/2·m·v²

By the principle of conservation of energy, we have;

The change (loss) in kinetic energy, ΔK.E. = The change (gain) in potential energy, ΔP.E.

ΔK.E. = 1/2·m·(v² - u²)

ΔP.E. = m·g·(h₂ - h₁)

Where;

h₁ = The ground level = 0 m

h₂ = The altitude with which she crosses the bar

∴ 1/2·m·(v² - u²) = m·g·(h₂ - h₁)

(h₂ - h₁) = (v² - u²)/(2·g) = (11² - 1.1²)/(2·9.8) = 6.11173469388

h₂ = 6.11173469388 + h₁ = 6.11173469388 + 0 = 6.11173469388

h₂ = 6.11173469388

Her altitude as she crosses over the bar, h₂ ≈ 6.1 m.

3 0

3 years ago

The energy of random atomic and molecular motion is called.

Vanyuwa [196]

Energy of a random atomic and molecular is called molecules energy

5 0

2 years ago

18)

Nina [5.8K]

Number 18 is C, i thin

5 0

3 years ago

Read 2 more answers

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1515

Talja [164]

Complete Question

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.

Answer:

The angle is

Explanation:

From the question we are told that

The light emerging from second Polaroid is 1/5 the unpolarized

Generally the intensity of light emerging from the first Polaroid is mathematically represented as

$I_1 = \frac{I_o}{ 2 }$

Generally from the Malus law the intensity of light emerging from the second Polaroid is mathematically represented

$I_2 = I_1 cos^2 (\theta )$

=> $cos^2 (\theta ) = \frac{I_2}{I_1 }$

=> $cos (\theta) = \sqrt{ \frac{I_2}{I_1} }$

From the question $I_2 = \frac{I_o}{5}$

$cos (\theta) = \sqrt{ \frac{ \frac{ I_o}{5} }{\frac{I_o}{2} } }$

$cos (\theta) = \sqrt{ \frac{2}{5} }$

=> $\theta = cos ^{-1} [\sqrt{\frac{2}{5}} ]$

=> $\theta = 50.77^o$

8 0

3 years ago