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Tamiku [17]
4 years ago
10

the acceleration on the moon is 1.6 m/s^2 what is the maximum height of a ball you throw at 20 m/s straight up?​

Physics
1 answer:
Artist 52 [7]4 years ago
3 0

Answer:

125 m

Explanation:

Given:

v₀ = 20 m/s

v = 0 m/s

a = -1.6 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (20 m/s)² + 2 (-1.6 m/s²) Δy

Δy = 125 m

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Hiran is standing beside the road when he hears a bird flying away from hip and chirping. The bird’s chirp has a frequency of 18
Murrr4er [49]

The frequency of bird chirping hear by hiran will be 1.77 kHz.

<u>Explanation:</u>

As per Doppler effect, the observer will feel a decrease in the frequency of the receiving signal if the source is moving away from the observer. So the shifted frequency is obtained using the below equation:

f'=\frac{c}{c+v_{s} }f

Here , c is the speed of sound, Vs is the velocity of source with which it is moving away. f is the original frequency of source and f' is the frequency shift heard by the observer.

As here, f = 1800 Hz, Vs= 6 m/s and c = 343 m/s, then

f'=\frac{343}{343+6} \times 1800=1.77\ kHz

So, the frequency of bird chirping hear by hiran will be 1.77 kHz.

4 0
3 years ago
When you rub a balloon on a sweater or your hair, the what is transferred to the balloon giving it a what charge. The balloon wi
Elis [28]

Answer:

When you rub a balloon on a sweater or your hair, the <u>electrons</u> are transferred to the balloon giving it a <u>negative</u> charge. The balloon will then <u>repel</u> any object that has a different charge.

hope this helps :)

5 0
3 years ago
Gravity is a <br><br> A.pushing force<br> B. not a force at all<br> C. pulling force
melamori03 [73]

Answer:

C

Explanation:

gravity is a pulling force according to Newton

4 0
3 years ago
Freeeeeeeee poinnttttsssss
RUDIKE [14]

Answer:

k

Explanation:

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5 0
3 years ago
A luggage handler pulls a 20.0 kg suitcase up a ramp inclined at 25 degrees above the horizontal by a force F of magnitude 145 N
Nonamiya [84]

Answer:

A) 667 J

B) 381.4 J

C) 0 J

D) 245.4 J

E) 40.2J

F) 2 m/s

Explanation:

Let g = 9.81 m/s2

A) The work done on the suitcase is the product of the force applied and the distance travelled:

w = Fs = 145 * 4.6 = 667 J

B) The work done by gravitational force the dot product between the gravity vector and the distance vector

W_g = \vec{P}\vec{s} = mgs sin\alpha = 20*9.81*4.6*sin25^o = 381.4 J

C) As the normal force vector is perpendicular to the distance vector, the work done by the normal force is 0

D) The work done on the suitcase by friction force is the product of the force applied and the distance travelled, whereas friction force is the product of normal force and coefficient

W_f = F_fs = \mu N s = \mu s mgcos\alpha = 0.3* 4.6 * 20*9.81*cos25^o = 245.4 J

E) The total workdone on the suite case would be the pulling work subtracted by gravity work and friction work

W = w – W_g – W_f = 667 – 381.4 – 245.4 = 40.2 J

F) As the suit case has 0 kinetic and potential energy at the bottom, and the total work done is converted to kinetic energy at 4.6 m along the ramp, we can conclude that:

E_k = W = 40.2 j

mv^2/2 = 40.2

20v^2/2 = 40.2

10v^2 = 40.2

v^2 = 4.02

v = \sqrt{4.02} = 2 m/s  

3 0
3 years ago
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