Answer:
I say 150 because i aded 850+150= 1000 so yea thats how i got my answer
Explanation:
Answer:
See Explanation
Explanation:
Solving (4): 0.84554 as a fraction
The above number is to 5 decimal places, so the fraction equivalent is:
Divide numerator and denominator by 2
Solving (5):
The midpoint, M is calculated as follows:
Where
The distance, D is calculated using:
Solving (1): The expression for f(x) is not clear. So, I'll make use of:
Substitute each value of the domain in
The range is:
Solving (2):
Shape: Open Cylinder
The surface area is calculated as:
Solving (3):
The value of a is not clear. So, I'll assume that a is a
Given that
Find
Substitute 3a for b
Absolute value of 4a is 4a. So,
Solving (9):
Given
--- Principal
--- Rate
--- Time in years
The amount (A) is calculated as follows:
Hence, the amount at the end of 2 years is:
Answer:
Explanation:
Start by finding the weight supported by the wheels, as we can then relate that to the total frictional force through the friction coefficient. This is given by:
W=mg
Substitute 1.00×, or 1,000, for m and 9.81 m/ for g. This gives us
W=(1,000)(9.81)
W=9,810 N
Since half the weight is supported by the wheels in question, we divide this by two, and the weight we will use is 4,905 N.
The frictional force is given by:
F=μW
Where μ is the friction coefficient and W is the weight, which we just calculated. The friction coefficient for rubber on dry concrete is given in Table 6.1 as (1.0). Substitute that for μ and 4,905 N for weight and we get the total frictional force as 4,905 N. Now we can find the acceleration by rearranging F=ma to get a=. Substitute our frictional force 4,905 N for F and our total mass 1,000 kg for m to get 4.9 m/.
KE=1/2mv^2
So the 3kg ball rolling at velocity of 3m/s has a KE=1/2(3)(3^2)=27/2=13.5J
The 2kg ball only has a KE=1/2(2)(3^2)=9J
So we can see the 3kg ball has more KE than the 2kg ball because they are moving at the same velocity so the bigger mass has more KE