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Brums [2.3K]
3 years ago
5

What are some of the useful properties of current electricity?

Physics
2 answers:
Elena-2011 [213]3 years ago
8 0

By definition we have to:

The electric current is the flow of electric charge due to the movement (usually of electrons) that a material travels.

Some properties are:

1) Electric conduction: The conductive materials have a large amount of free electrons, therefore, the passage of electricity is possible.

2) The current inside a circuit is directly proportional to the voltage and inversely proportional to the resistance of the circuit. This is what is known as ohm's law:

I =\frac{V}{R}

3) The current can be continuous or alternate.

Alternating current is the electric current in which the magnitude and direction vary cyclically.

The direct current is the flow of electric charges that does not change direction with time.

Art [367]3 years ago
6 0
<span>In simple words, current electricity is the flow of electrons through a conductor (wires). Following are the few properties of the current Electricity:

1. Potential Difference (also called as Voltage):
It is the difference in Electric potential between two points. Those two points might be the positive and the negative ends of a battery. Higher the difference, greater will be the energy (potential) of the electrons running through a wire. It is represented by V, and its unit is Volts.

2. Electric Current
It represents the number of electrons (charges) passing by a point per second. Its unit is Ampere, and it is represented by A.

3. Resistance
It represents the opposition that a substance offers to the flow of electric current. Its unit is Ohm, and it is represented by Ω.
</span>
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If an atom contains 13 protons, then it has (2.4)a.13 electrons. b. 26 electrons. c. 13 neutrons. d.26 neutrons.
Yuliya22 [10]

If an atom contains 13 protons, then it has <u>13 electrons.</u>

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3 years ago
A train 400 m long is moving on a straight track with a speed of 81.4 km/h. The engineer applies the brakes at a crossing, and l
Luda [366]

Answer:

86.5m

Explanation:

first convert km/h

then

81.4*1000/60*60=22.6

17.6*1000/60*60=4.89

then, x1/t1=x2/t2

we get

x2=400*4.89/22.6=86.5//

3 0
3 years ago
Derive the formula for the moment of inertia of a uniform, flat, rectangular plate of dimensions l and w, about an axis through
Ad libitum [116K]

Answer:

A uniform thin rod with an axis through the center

Consider a uniform (density and shape) thin rod of mass M and length L as shown in (Figure). We want a thin rod so that we can assume the cross-sectional area of the rod is small and the rod can be thought of as a string of masses along a one-dimensional straight line. In this example, the axis of rotation is perpendicular to the rod and passes through the midpoint for simplicity. Our task is to calculate the moment of inertia about this axis. We orient the axes so that the z-axis is the axis of rotation and the x-axis passes through the length of the rod, as shown in the figure. This is a convenient choice because we can then integrate along the x-axis.

We define dm to be a small element of mass making up the rod. The moment of inertia integral is an integral over the mass distribution. However, we know how to integrate over space, not over mass. We therefore need to find a way to relate mass to spatial variables. We do this using the linear mass density of the object, which is the mass per unit length. Since the mass density of this object is uniform, we can write

λ = m/l (orm) = λl

If we take the differential of each side of this equation, we find

d m = d ( λ l ) = λ ( d l )

since  

λ

is constant. We chose to orient the rod along the x-axis for convenience—this is where that choice becomes very helpful. Note that a piece of the rod dl lies completely along the x-axis and has a length dx; in fact,  

d l = d x

in this situation. We can therefore write  

d m = λ ( d x )

, giving us an integration variable that we know how to deal with. The distance of each piece of mass dm from the axis is given by the variable x, as shown in the figure. Putting this all together, we obtain

I=∫r2dm=∫x2dm=∫x2λdx.

The last step is to be careful about our limits of integration. The rod extends from x=−L/2x=−L/2 to x=L/2x=L/2, since the axis is in the middle of the rod at x=0x=0. This gives us

I=L/2∫−L/2x2λdx=λx33|L/2−L/2=λ(13)[(L2)3−(−L2)3]=λ(13)L38(2)=ML(13)L38(2)=112ML2.

4 0
2 years ago
I need so much help 50 points!!!!!!<br><br>complete the graph
motikmotik

<u>First Symbol </u>: Cobalt (Co)

Its Group Number - 9

Its Period Number - 4

Its Family Name - Transition Metal

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Its Period Number - 2

Its Family Name - Semiconductor

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Its Group Number - 17

Its Period Number - 6

Its Family Name - Halogen

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Its Group Number - 2

Its Period Number - 3

Its Family Name - Alkaline Earth Metal

<u>Fifth Symbol</u> : Xenon (Xe)

Its Group Number - 18

Its Period Number - 5

Its Family Name - Noble Gas

6 0
3 years ago
Why are atoms in a covalent bond usually a certain distance away from each other?
ANTONII [103]
I think it is because the electrons repel each other

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3 years ago
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