<span>carrying twice the weight and climbing twice as high</span>
Answer:
12 nC
Explanation:
Capacity of the parallel plate capacitor
C = ε₀ A/d
ε₀ is constant having value of 8.85 x 10⁻¹² , A area of plate , d is distance between plate
Area of plate = π r²
= 3.14 x (0.8x 10⁻²)²
= 2 x 10⁻⁴
C = ( 8.85 X 10⁻¹² x 2 x 10⁻⁴ ) / 2.8 x 10⁻³
= 7.08 x 10⁻¹³
Potential difference between plate = field strength x distance between plate
= 6 x 10⁶ x 2.8 x 10⁻³
= 16.8 x 10³ V
Charge on plate = CV
=7.08 x 10⁻¹³ X 16.8 X 10³
11.9 X 10⁻⁹ C
12 nC .
Answer:
N
N
Explanation:
= 1 A
= 4 A
= distance between the two wire = 5 m
= Force per unit length acting between the two wires
Force per unit length acting between the two wires is given as


N
= distance of each wire from the midpoint = 2.5 m
Magnetic field midway between the two wires is given as



The answer is volt for this question.
I hope is correct if not I’m sorry.