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Leni [432]
3 years ago
11

cogeneration plants are different from regular commercial generating stations because the heat, after it generates electricity,

is later sold to a(n)_____?
Physics
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

Central heating plant or manufacturer.

Explanation:

Co generation plants are useful in the sense that they do not let the thermal energy wasted for heating, they utilize it. They use that heat to drive the steam or gas turbine- powered generators. However the regular commercial generating stations do not do that.

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C. example. honey has a higher viscosity than water.
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If you see a crosswalk signal flashing, you should look out for:
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C.) Pedestrians yielding to cross traffic.

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Bryan Allen pedaled a human-powered aircraft across the English channel from the cliffs of Dover to Cap Gris-Nez on June 12, 197
tigry1 [53]

Answer:

The answer is "5.53 \ \frac{m}{s}"

Explanation:

apply the formula for calculating the average velocity to the relative air

V_{PG} =V_{PA}+V_{AG}

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V_{AG} = -2 \ \frac{m}{s}

V_{PG} =3.53

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4 0
2 years ago
A puddle of water has a thin film of gasoline floating on it. A beam of light is shining perpendicular on the film. If the wavel
erastovalidia [21]

Answer:

D.

Explanation:

To solve the problem it is necessary to apply the concepts of Destructive and constructive interference. The constructive interference in tin film is given by

2t = (m+\frac{1}{2})\frac{\lambda}{n}

Where,

t = thickness

\lambda=Wavelenght

m= is an integer

n= film/refractive index

We use this equaton because phase change is only present for gasoline air interface, but not at the gasoline-water interface. <em>The minimum t only would be when the value of m=0 then</em>

2nt = \frac{\lambda}{2}

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4 0
3 years ago
A crane used 250,000 Joules of work to move a beam to the top of a building in 20 seconds. How much power did the crane use?
maria [59]

Answer:

12500W

Explanation:

Given parameters:

Work done  = 250000J

Time taken  = 20s

Unknown:

Power of the crane = ?

Solution:

Power is the defined as the rate at which work is being done;

  Mathematically;

        Power = \frac{work done}{time }

 insert the parameters and solve;

      Power  = \frac{250000}{20}   = 12500W

7 0
3 years ago
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