The greater the difference in electronegativity (ΔEN) between two atoms, the greater the degree in ionic character in the bond.
If you have a bond between atoms A and B (A-B),
ΔEN = |EN_A - EN_B|
The rules for the type of bond are:
• If ΔEN < 0.5, the bond is nonpolar covalent
• If 0.5 ≤ΔEN < 1.7, the bond is polar covalent
• If ΔEN ≥ 1.7, the bond is ionic
<em>Examples:
</em>
<em>C-H</em>: ΔEN = |2.55 – 2.20| = 0.35; <em>nonpolar covalent
</em>
<em>C-F</em>: ΔEN = |2.55 – 3.98| = 1.43; <em>polar covalent</em>
<em>Na-F</em>: ΔEN = |0.93 – 3.98| = 3.05; <em>ionic
</em>
Answer: 63.88 atm
Explanation:
To answer this, we use the formula PV = nRT since the asumption is that the gas has an ideal behavior
where number of mole = 2.60 mol, R(gas constant) = 0.08205746 L atm/K mol,
T = 251 ∘C = (251 + 273) K = 524 K, Volume = 1.75 L
Making Pressure the subject of the formula, we have
P = nRT/V = 2.6 * 0.08205746 * 524/2.75 = 63.88 atm
Answer:
Yes chemistry. Try to add then multiply the top. Get the moles and you will find it.
Explanation:
Try to add then multiply the moles in the equation
Answer:
20.2 kJ
Explanation:
Based on the information in the reaction, the amount of heat released per mole of Na₂O₂ (the molar enthalpy) is calculated as follows:
126 kJ / 2 mol = 63 kJ/mol Na₂O₂
The number of moles in 25.0g of Na₂O₂ must be calculated using the molecular weight of Na₂O₂ (77.978 g/mol):
(25.0 g)/(77.978 g/mol) = 0.32060 mol Na₂O₂
Thus, the heat released will be:
(63 kJ/mol)(0.32060 mol) = 20.2 kJ
