Question

Calculate the linear momentum for each of the following cases. (a) A proton with mass 1.67 ✕ 10-27 kg moving with a velocity of 5.04 ✕ 106 m/s straight up. kg·m/s upward (b) A 15.0 g bullet moving with a velocity of 315 m/s to the right kg·m/s to the right (c) A 71 kg sprinter running with a velocity of 6.6 m/s southwest. kg·m/s southwest (d) Earth (m = 5.98 ✕ 1024 kg) moving in its orbit with a velocity equal to 2.98 ✕ 104 m/s forward. kg·m/s forward

Answer 1

Answer:

$8.4168\times 10^{-21}\ kgm/s$ upward

4.725 kgm/s to the right

468.6 kgm/s southwest

$1.782\times 10^{49}\ kgm/s$ forward

Explanation:

When the mass of an object is multiplied by its velocity we get momentum

m = Mass

v = Velocity

Proton

$p=mv\\\Rightarrow p=1.67\times 10^{-27}\times 5.04\times 10^6\\\Rightarrow p=8.4168\times 10^{-21}\ kgm/s$

The momentum of the proton is $8.4168\times 10^{-21}\ kgm/s$ upward

Bullet

$p=mv\\\Rightarrow p=0.015\times 315\\\Rightarrow p=4.725\ kgm/s$

The momentum of the bullet is 4.725 kgm/s to the right

Sprinter

$p=mv\\\Rightarrow p=71\times 6.6\\\Rightarrow p=468.6\ kgm/s$

The momentum of the sprinter is 468.6 kgm/s southwest

Earth

$p=mv\\\Rightarrow p=5.98\times 10^{24}\times 2.98\times 10^4\\\Rightarrow p=1.782\times 10^{29}\ kgm/s$

The momentum of the sprinter is $1.782\times 10^{29}\ kgm/s$ forward