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bagirrra123 [75]

3 years ago

7

Calculate the linear momentum for each of the following cases. (a) A proton with mass 1.67 ✕ 10-27 kg moving with a velocity of

5.04 ✕ 106 m/s straight up. kg·m/s upward (b) A 15.0 g bullet moving with a velocity of 315 m/s to the right kg·m/s to the right (c) A 71 kg sprinter running with a velocity of 6.6 m/s southwest. kg·m/s southwest (d) Earth (m = 5.98 ✕ 1024 kg) moving in its orbit with a velocity equal to 2.98 ✕ 104 m/s forward. kg·m/s forward

1 answer:

Oliga [24]3 years ago

4 0

Answer:

$8.4168\times 10^{-21}\ kgm/s$ upward

4.725 kgm/s to the right

468.6 kgm/s southwest

$1.782\times 10^{49}\ kgm/s$ forward

Explanation:

When the mass of an object is multiplied by its velocity we get momentum

m = Mass

v = Velocity

Proton

$p=mv\\\Rightarrow p=1.67\times 10^{-27}\times 5.04\times 10^6\\\Rightarrow p=8.4168\times 10^{-21}\ kgm/s$

The momentum of the proton is $8.4168\times 10^{-21}\ kgm/s$ upward

Bullet

$p=mv\\\Rightarrow p=0.015\times 315\\\Rightarrow p=4.725\ kgm/s$

The momentum of the bullet is 4.725 kgm/s to the right

Sprinter

$p=mv\\\Rightarrow p=71\times 6.6\\\Rightarrow p=468.6\ kgm/s$

The momentum of the sprinter is 468.6 kgm/s southwest

Earth

$p=mv\\\Rightarrow p=5.98\times 10^{24}\times 2.98\times 10^4\\\Rightarrow p=1.782\times 10^{29}\ kgm/s$

The momentum of the sprinter is $1.782\times 10^{29}\ kgm/s$ forward

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a) A polarized is a system that absorbs light that is not polarized in the direction of its axis, therefore half of the non-polarized light must be absorbed

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A girl coasts down a hill on a sled, reaching level ground at the bottom with a speed of 7.4 m/s. The coefficient of kinetic fri

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Answer: 62.22 meters

Explanation:

Two solve this, we need to know first how the Sled interact with the snow. While the Sled runs over the snow, the snow opposes to it movement, this is call friction. Frictions creates is a force that goes against any movement and is caused by the interaction between surfaces.

Friction can be calculated using the following equation:

Friction's Force (Ff) = m*N

Where m is the Frictions coficient and N is call Normal, which is a force created by the contact between any weight and a surface. Because the sled is and the surface are totally horizontal, the Normal is equal to the Sled's Weight.

So for this case, we can calculate the Friction's Force:

Ff = 0.045 * 735 N

Ff = 33,07 N

This force will cause a negative acceleration the Sled causing it to slow down and finally stop. To know this accelaration we can use the following equation:

Force (F) = Mass (m) * Accelaration (a)

Looking for the accelaration:

Acceleration (a) = F / M

As a side note:

Mass (M) = F / a (1)

Where we know that F is equal to our Friction Force (Ff) and the Mass for the girl and the Sled can be obtained using the previous equation (1) like this

Girl and sled Mass (M) = 735 N / (9.81 m/s)

M = 74,92 Kg

This is posible, because the Girl and The Sled are aplying a Force on the ground equal to 735 N. The accelartion for their mass is the gravity

Now, with the mass we can found the Accelaration caused by friction:

Acceleration (a) = Ff / M

Accelaration (a) = 33,07 N / 74,92 Kg

a = 0,44 $m/s^{2}$

To know how far the Sled travel we can use the following equation:

$V_{f} ^{2} = V_{0} ^{2} + 2ax$

Where Vf is the Final Velocity, which is when the sled finally stops (Vf = 0), Vo is the Initial Speed of the Sled equal to 7.4 m/s and a is equal to the negative accelaration that causes the friction.

$(0)^{2} = (7.4 m/s)^{2} + 2(-0,44)x$

Searching for x:

$x = \frac{0 - (7.4 m/s)^{2} }{-0.88}$

$x = \frac{0 - (7.4 m/s)^{2} }{-0.88}$

$x = \frac{0 - (7.4 m/s)^{2} }{-0.88}$

$x = 62.22 meters$

The girls will run over the snow 62.22 meter until finally stopping

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