All categories

2 years ago

Write the energy conversion when a moving car braking to stop completely

Physics

1 answer:

bixtya [17]2 years ago

8 0

Answer:

Friction braking is the most commonly used braking method in modern vehicles. It involves the conversion of kinetic energy to thermal energy by applying friction to the moving parts of a system. The friction force resists motion and in turn generates heat, eventually bringing the velocity to zero.

You might be interested in

For the following question, two statements are given- one labelled Assertion (A) and the other labelled Reason (R). Select the c

AleksandrR [38]

Answer:

assertion is true but the reason is not true

Explanation:

5 0

3 years ago

A tennis ball with a speed of 11.3 m/s is moving perpendicular to a wall. after striking the wall, the ball rebounds in the oppo

Arlecino [84]

To calculate the average acceleration of the ball we use the formula,

$a= \frac{v_{f} -v_{i}}{t}$

Here, $v_{f}$ is the final velocity of the ball and $v_{i}$ is the initial velocity of the ball t is the time in contact with the wall.

Given $v_{i} = 11.3 m/s$ towards the wall and $v_{f} = 7.2207 m/s$

away from the wall and $t=0.00803 s$ .

Substituting these values in above formula , we get

$a=\frac{(-7.2207 m/s)-11.3 m/s}{0.00803 s}$

Here $v_{f}$ is negative because ball is moving away from the wall.

$a= - 2306 .4 \ m/s^{2}$

Therefore, average acceleration of the ball is $- 2306 .4 \ m/s^{2}$ (away from the wall).

4 0

4 years ago

The masses of the Earth and Moon are 5.98×1024kg and 7.35×1022kg respectively, and their centers are separated by 3.84×108m.

bija089 [108]

Answer:

C) The Earth-Moon CM follows the orbit around the Sun. Earth and Moon rotate around their CM. The radius of rotation of Moon around the CM is much greater than radius of rotation of Earth around the CM.

Explanation:

At first we assume that both Earth and Moon can be treated as particles, the center of mass of the Earth-Moon system is obtained by using this formula:

$r_{CM} = \frac{r_{E}\cdot m_{E}+r_{M}\cdot m_{M}}{m_{E}+m_{M}}$ (Eq. 1)

Where:

$r_{E}$ - Location of the center of the Earth, measured in kilometers.

$r_{M}$ - Location of the Moon, measured in kilometers.

$r_{CM}$ - Location of the center of mass, measured in kilometers.

$m_{E}$ - Mass of the Earth, measured in kilograms.

$m_{M}$ - Mass of the Moon, measured in kilograms.

If we know that $r_{E} = 0\,km$ , $r_{M} = 3.84\times 10^{8}\,m$ , $m_{E} = 5.98\times 10^{24}\,kg$ and $m_{M} = 7.35\times 10^{22}\,kg$ , the location of the center of mass respect to the Earth is:

$r_{CM} = \frac{(0\,km)\cdot (5.98\times 10^{22}\,kg)+(3.84\times 10^{8}\,m)\cdot (7.35\times 10^{22}\,kg)}{5.98\times 10^{24}\,kg+7.35\times 10^{22}\,kg}$

$r_{CM} = 4.662\times 10^{6}\,m$

The Earth has a radius of $6.371\times 10^{6}$ meters, we notice that center of mass in located inside the Earth and the radius of rotation of the Earth around the center of mass is much greater than the radius of rotation of the Moon around the center of mass. That center of mass follows an orbit around the sun.

In consequence, correct answer is C.

4 0

3 years ago

A long-distance runner is running at a constant speed of 5 m/s.

vivado [14]

Answer:

3.33 minutes (3 minutes and 20 seconds)

Explanation:

Speed of the runner = s = 5 m/s

We need to calculate how will it take for runner to complete 1 km. We have the speed, the distance and we need to find the time. Before performing any calculations, we must convert the values to same units.

Speed is in m/s and distance is in kilometers. So we have to either convert speed to km/s or distance into meters. In this case, converting distance into meters would be a convenient option.

1 kilo meters = 1000 meters

The distance, speed and time are related by the equation:

Distance = Speed x Time

So,

Time = Distance/Speed

Using the values, we get:

t = 1000/5

t = 200 seconds

This means, the runner can complete 1 kilometers in 200 seconds. Since, there are 60 seconds in a minute, we can convert this time to minutes, by dividing it by 60. i.e.

$200 \text{ sec} = \frac{200}{60} \text{ min} = 3.33 \text{ min}$

Thus, it will take the runner 3.33 minutes (3 minutes and 20 seconds) to travel 1 km.

3 0

3 years ago

A motorcycle travels 90.0 km/h. How many seconds will it take the motorcycle to cover 2.10 x 103 m?

mina [271]

Answer:

The time taken is 84 seconds, please give the brainliest award would be much appreciated.

4 0

3 years ago

Write the energy conversion when a moving car braking to stop completely​

Write the energy conversion when a moving car braking to stop completely