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baherus [9]
3 years ago
12

Question 4 of 20 : Select the best answer for the question. 4.   Which of the following would lower the pitch of a string instru

ment's sound?        A. shortening the effective string length.   B. increasing the thickness of the string used.   C. adding tension within the string.   D. using less force to vibrate the string
Physics
1 answer:
Nady [450]3 years ago
4 0
The correct option is B.
There are four basic factors which affect the properties of stringed instruments, these are frequency, diameter [thickness], tension and density.
Diameter refers to the thickness of the string. Thick strings with large diameter vibrate slower and thus they have lower frequency and lower pitch compared with thin strings.<span />
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Lukalu is rappelling off a cliff. The parametric equations that describe her horizontal and vertical position as a function of t
andre [41]

Answer:

2.5 s, 5 m

Explanation:

The equations for the horizontal and vertical position of Lukalu are:

x(t) = 8t\\y(t) = -16t^2 + 100

we can find the time it takes her to reach the ground by requiring that the vertical position becomes zero:

y(t) = 0

So we find:

0=-16t^2 +100\\16t^2 = 100\\t=\sqrt{\frac{100}{16}}=2.5 s

The horizontal distance of Lukalu instead will be given by the equation for the horizontal position, substituting t = 2.5 s:

x=8t = 8 \cdot 2.5 s =5 m

4 0
3 years ago
Children in a tree house lift a small dog in a basket 4.00 m up to their house. If it takes 187 J of work to do this, what is th
Vika [28.1K]
A=Fh
A - work
F - force
h - distance

F=mg
m - mass (god+basket)

so
A=mgh
187 = m*10*4
187=40m
m=187/40
m=4.675 kg
or 4kg and 675g

pretty small dog...
6 0
3 years ago
A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin
Lubov Fominskaja [6]

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

\tau=F\times r

\tau=mg\times r

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

\tau=54\times9.8\times0.050

\tau=26.46\ N-m

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0
3 years ago
What must be done to the wires used to make an electromagnet before they are connected​
dalvyx [7]

Answer:

Neatly wrap the wire around the nail

Explanation:

hope this helps ( not sure tho )

5 0
3 years ago
Read 2 more answers
A 9.6 cm diameter circular loop of wire is in a 1.10 T magnetic field perpendicular to the plane of the loop. The loop is remove
Natali5045456 [20]

Answer:

Thus induced emf is 0.0531 V

Solution:

As per the question:

Diameter of the loop, d = 9.6\ cm = 0.096\ m

Thus the radius of the loop, R = 0.048 m

Time in which the loop is removed, t = 0.15 s

Magnetic field, B = 1.10 T

Now,

The average induced emf, e is given by Lenz Law:

e = - \frac{\Delta \phi_{B}}{\Delta t}

e = - \frac{\Delta \phi_{B}}{\Delta t}

where

\phi_{B} = magnetic flux = A\Delta B

where

A = cross sectional area

Also, we know that:

e = - \frac{A\Delta B}{\Delta t}

e = - \frac{\pi r^{2}\times (0 - 1.10)}{0.15}

e = - \frac{\pi \times 0.048^{2}\times (0 - 1.10)}{0.15}

e = 0.0531 V

The sketch is shown in the figure, where I indicates the direction of the induced current.

3 0
3 years ago
Read 2 more answers
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