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vodka [1.7K]
3 years ago
11

In the compound mgo magnesium has an oxidation number of __________

Chemistry
2 answers:
Vitek1552 [10]3 years ago
8 0
In the compound Mgo magnesium has an oxidation number of 2 apex
Alexxx [7]3 years ago
4 0

Answer : The oxidation number of magnesium in MgO is, (+2).

Explanation :

Oxidation number : The oxidation number represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

The oxidation number of  oxygen (O)  in compounds is usually -2.

The given compound is, MgO

Let the oxidation state of 'Mg' be, 'x'

x+(-2)=0\\\\x-2=0\\\\x=+2

Therefore, the oxidation number of magnesium (Mg) in MgO is, (+2)

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A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrat
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Answer:

<u> </u><u>85.952 ml</u> Zn^2^+  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

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As the number of moles of CoSO_4 =\frac{Given mass }{molar mass}

                                                       =\frac{1.817}{155}

                                                          =0.01172

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           =\frac{0.01172}{20}

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Excess of EDTA = concentration of EDTA - concentration of CoSO4

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                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 (Zn^2^+)

           0.008419\times100ml=0.009795\times V2

           V2=\frac{0.008419\times100}{0.009795}

             V2 =85.952 ml

Therefore , <u>85.952 ml </u>Zn^2^+ needed to titrate the excess complexing reagent .

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