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Alja [10]
3 years ago
13

what is the method of the slope stabilization, and how many type of method of the stabilization, please help explain the types o

f the methods clearly? thnk u​
Engineering
1 answer:
Alik [6]3 years ago
5 0

Answer:

1.Plant Grass and Shrubs. Grass and shrubs are very effective at stopping soil erosion. ...

2.Use Erosion Control Blankets to Add 3.Vegetation to Slopes. ...

4.Build Terraces. ...

5.Create Diversions to Help Drainage

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Coulomb's Law Two point charges experience an attractive force of 10.8 N when they are separated by 2.4 m. VWhat force in newton
SashulF [63]

Answer:

The force between the charges when the separation decreases to 0.7 meters equals 126.955 Newtons

Explanation:

We know that for two point charges of magnitude q_{1},q_{2} the magnitude of force between them is given by

F=\frac{k_{e}q_{1}\cdot q_{2}}{r^{2}}

where

k_{e} is constant

r is the separation between the charges

Initially when the charges are separated by 2.4 meters the force can be calculated as

F_{1}=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\10.8=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\\therefore k_{e}\cdot q_{1}q_{2}=10.8\times 2.4^{2}=62.208

Now when the separation is reduced to 0.7 meters the force is similarly calculated as

F_{2}=\frac{k_{e}\cdot q_{1}q_{2}}{0.7^{2}}

Applying value of the constant we get

F_{1}=\frac{62.208}{0.7^{2}}

Thus F_{2}=126.955Newtons

5 0
3 years ago
A rigid canister with a radius of 5 in and a height of 10 in is filled with air. The initial pressure and temperature of air in
Elza [17]

Answer:1.458 Btu

Explanation:

Given

radius of canister\left ( r\right )=5in

Height of canister\left ( h\right )=10 in.

Initial pressure\left ( P_i\right )=14.7 Psi

Initia ltemprature\left ( T_i\right )=70^{\circ}F

Final pressure\left ( P_f\right )=30Psi

as canister is rigid therefore change in volume is zero

therefore

\frac{P_i}{T_i}=\frac{P_f}{T_f}

\frac{14.7}{70}=\frac{30}{T_f}

T_f=142.85^{\circ}F

volume of canister=\pi \times r^{2}\times h

                               =\pi \times 5^{2}\times 10=250\pi

volume of canister=12872,038.8 mm^3

now calculating mass of air

PV=mRT

substituting values

\left ( 14.7Psi\right )\left ( 12872,038.8 mm^3\right )=m\left ( 0.287\right )\left ( 70^{\circ}F\right )

m=21.0192 gm

Therefore heat transferred =mc_p\left ( T_f-T_i\right )

                                             =21.0192\times 10^{-3}\times \left ( 142.857-70\right )

                                             =1539.052J=1.458Btu

3 0
4 years ago
A single-degree-of-freedom mass-spring-damper system is observed during its free vibration and the displacement amplitude decays
AleksandrR [38]

Answer:

Logarithmic decrement is equal to 0.182

Explanation:

given,

amplitude decay = 9 dB          

number of cycles = 12 cycles        

mass of the system = 7 kg        

spring stiffness = 3000 N/m            

logarithmic decrement = ?                  

now,                                                      

logarithmic decreament = ln\ D^{\frac{1}{n}}

                                        = ln\ 9^{\frac{1}{12}}

                                        =ln (1.2)

                                        = 0.182

Hence, Logarithmic decrement is equal to 0.182

5 0
4 years ago
A rigid, insulated tank that is initially evacuated is connected through a valve to a supply line that carries helium at 200 kPa
Aleks04 [339]

Answer: a 8143.71 kJ/kg

b 393.15 K

Explanation:

This system is an isobaric process in which there is no change in pressure a quasistatic process where a pressure distribution exists

a since no change in pressure =0 the system does work thus

FOR HELIUM  properties in standard thermodynamic chart

cv = 3.1 kJ/kgK

M = Molar mass = 4 kg/kmol

R = Universal gas constant = 8.314 kJ/kg K

cp ≈ cv +R /M = 3.1 + 8.314 /4 = 5.1785 kJ/kgK  

Cp = cp * M = 5.1785 kJ/kgK * 4 kg/kmol  = 20.714 kJ/kgkmol

T = 120  °C  to Kelvin = 120 + 273.15k = 393.15 K

W =n Cp ΔT = 1 kmol * 20.714 kJ/kg kmol* 393.15 K = 8143.71 kJ/kg

b convert T °C = T K thus 120 + 273.15 K = 393.15 K

P₁/T₁ = P₂/T₂

200 kPa/ 393.15 K = 200 kPa/T₂

T₂ = 200 kPa * 393.15 K/ 200 kPa = 393.15 K or 120 k

7 0
4 years ago
Why are today’s homes more likely to have dangerous levels of carbon monoxide than older homes?
Margarita [4]

Answer:

Carbon monoxide has no odor, color or taste,so  it cannot be detected by our senses. This means that dangerous concentrations of the gas can build up indoors and humans have no way to detect the problem until they become ill.

4 0
3 years ago
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