Answer:
Explanation:
The pump is modelled after applying Principle of Energy Conservation, whose form is:
The head associated with the pump is cleared:
Inlet and outlet velocities are found:
Now, the head associated with the pump is finally computed:
The power that pump adds to the fluid is:
Answer:
Explanation:
Given that
Unit cell is in FCC
Here given direction is not clear visible so we take direction [001].
We know that linear density(LD) given as
![LD=\dfrac{Number\ of\ atoms\ in\ the\ direction\ vector}{d_{[001]}}](https://tex.z-dn.net/?f=LD%3D%5Cdfrac%7BNumber%5C%20of%5C%20atoms%5C%20in%5C%20the%5C%20direction%5C%20vector%7D%7Bd_%7B%5B001%5D%7D%7D)
So the number of atom will be 1/2 in direction [001]
In FCC
B. If you do 39-3/4 divided by 12-1/2 you get 3.18
Answer:
Answer: (a) = 3.8187m/s, (b) =24.0858m/s (c) = = 3220.071m/s
Explanation:
du/u² = dt = ∫du/2.3183 = ∫dt
0.4313 u = t + c
(a) t = 0, u= 15m/s, c = 0.647
u = t+c/0.4313 = t + 0.647/0.4313
(a) when t= 1 u = 1+ 0.647/0.4313 = 3.8187m/s
(b) when t= 10 u = 10 + 0.647/0.4313 = 24.0858m/s
(c)when t= 1000 u = 1000 + 0.647/0.4313 = 3220.071m/s
Answer:
0.2 x 100
Explanation:
Engineering strain is the original crossection/original crossection
cold work percentage is
original crossection/original crossection x 100
