Answer:
The equation used to solve a diode is
![i_d = I_se^\frac{V_d}{V_T}-1](https://tex.z-dn.net/?f=i_d%20%3D%20I_se%5E%5Cfrac%7BV_d%7D%7BV_T%7D-1)
is the current going through the diode
is your saturation current
is the voltage across your diode
is the voltage of the diode at a certain room temperature. by default, you always use
for room temperature.
If you look at the equation,
, you'd notice that the
grow exponentially fast, so we can ignore the -1 in the equation because it's so small compared to the exponential.
![i_d = I_se^\frac{V_d}{V_T}-1](https://tex.z-dn.net/?f=i_d%20%3D%20I_se%5E%5Cfrac%7BV_d%7D%7BV_T%7D-1)
![i_d\approx I_se^\frac{V_d}{V_T}](https://tex.z-dn.net/?f=i_d%5Capprox%20I_se%5E%5Cfrac%7BV_d%7D%7BV_T%7D)
Therefore, use
to solve your equation.
Rearrange your equation to solve for
.
![V_D=V_Tln(\frac{i_D}{I_s})](https://tex.z-dn.net/?f=V_D%3DV_Tln%28%5Cfrac%7Bi_D%7D%7BI_s%7D%29)
a.)
i.)
You're given ![I_s=10^{-11}A](https://tex.z-dn.net/?f=I_s%3D10%5E%7B-11%7DA)
at
, ![V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{10\cdot10^{-6}}{10\cdot10^{-11}})=.298V](https://tex.z-dn.net/?f=V_D%3DV_Tln%28%5Cfrac%7Bi_D%7D%7BI_s%7D%29%3D%2825.9%5Ccdot10%5E%7B-3%7D%29ln%28%5Cfrac%7B10%5Ccdot10%5E%7B-6%7D%7D%7B10%5Ccdot10%5E%7B-11%7D%7D%29%3D.298V)
at
, ![V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{100\cdot10^{-6}}{10\cdot10^{-11}})=.358V](https://tex.z-dn.net/?f=V_D%3DV_Tln%28%5Cfrac%7Bi_D%7D%7BI_s%7D%29%3D%2825.9%5Ccdot10%5E%7B-3%7D%29ln%28%5Cfrac%7B100%5Ccdot10%5E%7B-6%7D%7D%7B10%5Ccdot10%5E%7B-11%7D%7D%29%3D.358V)
at
, ![V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{1\cdot10^{-3}}{10\cdot10^{-11}})=.417V](https://tex.z-dn.net/?f=V_D%3DV_Tln%28%5Cfrac%7Bi_D%7D%7BI_s%7D%29%3D%2825.9%5Ccdot10%5E%7B-3%7D%29ln%28%5Cfrac%7B1%5Ccdot10%5E%7B-3%7D%7D%7B10%5Ccdot10%5E%7B-11%7D%7D%29%3D.417V)
<em>note: always use</em> ![V_T=25.9mV](https://tex.z-dn.net/?f=V_T%3D25.9mV)
ii.)
Just repeat part (i) but change to ![I_s=-5\cdot10^{-12}A](https://tex.z-dn.net/?f=I_s%3D-5%5Ccdot10%5E%7B-12%7DA)
b.)
same process as part A. You do the rest of the problem by yourself.
Answer:
The answer is below
Explanation:
Absolute temperature is the temperature of a body with reference to 0 as the absolute zero.
English system of measurement are measurements used in united states while the S.I units are units that are universally accepted.
The temperature scale in S.I are Celsius (°C) for ordinary temperature and kelvin(K) for absolute temperature while the temperature scale in English system is Fahrenheit (°F) for ordinary temperature and Rankine (R) for absolute temperature.
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Explanation:
उह्ह्नमजज्ल्ह्ह्बनुतनकुहक्जो