Answer:
Average atomic mass = 55.83 amu
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope, Fe-54:
% = 6 %
Mass = 53.94 amu
For second isotope, Fe-56:
% = 92 %
Mass = 55.93 amu
For third isotope, Fe-57:
% = 2 %
Mass = 56.94 amu
Thus,
<u>Average atomic mass = 55.83 amu</u>
The basic unit of mass in the metric system is grams
<span>In thermodynamics, the internal energy of a thermodynamic system, or a body with well-defined boundaries, denoted by U, or sometimes E, is the total of the kinetic energy due to the motion of molecules (translational, rotational, vibrational) and the potential energy associated with the vibrational and electric energy of atoms within molecules or crystals. It includes the energy in all the chemical bonds, and the energy of the free, conduction electrons in metals.</span>
The answer would be 76.752 .
Answer:
The concentration is 
Explanation:
From the question we are told that
The absorbance is 
The length is 
Generally absorbance is mathematically represented as

where
is the molar absorptivity of FeSCN2 with a value 
and
is the equilibrium concentration of FeSCN2
So

substituting values

