A. When the substance is in its gaseous state.
<u>Explanation:</u>
When a substance is expanding against its constant volume and pressure, its temperature increases except when the substance is in gaseous state and not in liquid or solid state. So the internal energy increase in the system not only increases and maintaining the volume and pressure of the system remains constant in its gaseous phase. In the first law of Thermodynamics, it is used specifically that to especially in the case of gaseous system.
<u></u>
Answer:
4202.1 K
Explanation:
From;
PV=nRT
P= pressure of the gas = 18.5 bar
V = volume of the gas = 115L
n= number of moles of the gas = 6.1 mole
T= temperature of the gas = ?
R = gas constant = 0.083 L⋅bar⋅K−1⋅mol−1
T = PV/nR
T = 18.5 * 115/6.1 * 0.083
T = 2127.5/0.5063
T= 4202.1 K
As you get higher the atmospheric pressure lowers. The pressure in the packet of crisps has the pressure at which it has been closed (pressure at the surface of the earth). This means that the air molecules in the packet press harder outside than the air molecules in the atmosphere press on the packet.
Answer:
AYYYY I NEED POINST NOW NOW NO WNO WNOW
Explanation:
Answer:
.0027 M
Explanation:
We must calculate the threshold concentration of PO3−4 using Ksp and the given concentration of Ca2+:
Ca3(PO4)2(s)⇌3Ca2+(aq)+2PO3−4(aq)
Ksp=8.6×10−19=[Ca2+]3[PO3−4]2=(4.9×10−5M)3[PO3−4]2
[PO3−4]=0.0027 M
