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2 years ago

The ocean may pull away rom the shore as a tsunami approaches?

Physics

2 answers:

ale4655 [162]2 years ago

6 0

Uh if theres a tsunami it probably will.

Firlakuza [10]2 years ago

4 0

Yes that is what occurs when a tsunami comes

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What happens to the force between two charges if one of the charges are doubled?

Julli [10]

Answer:

The new force between the charges becomes double of the initial force.

Explanation:

The force acting between charge particles is given by :

$F=k\dfrac{q_1q_2}{r^2}$

k is electrostatic constant

r is distance between charges

If one of the charges are doubled, then, q₁ = 2q₁

The new force becomes,

$F'=\dfrac{2kq_1q_2}{r^2}\\\\F'=2F$

So, the new force between the charges becomes double of the initial force.

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3 years ago

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Mariulka [41]

Answer:

Acceleration

Explanation:

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3 years ago

A parallel-plate capacitor stores charge Q. The capacitor is then disconnected from its voltage source, and the space between th

Stells [14]

Answer:

The relationship between the initial stored energy $PE_{i}$ and the stored energy after the dielectric is inserted $PE_{f}$ is:

c) $PE_{f} =0.5\ PE_{i}$

Explanation:

A parallel plate capacitor with $C_{o}$ that is connected to a voltage source $V_{o}$ holds a charge of $Q_{o} =C_{o} V_{o}$ . Then we disconnect the voltage source and keep the charge $Q_{o}$ constant . If we insert a dielectric of $\kappa=2$ between the plates while we keep the charge constant, we found that the potential decreases as:

$V=\frac{V_{o}}{\kappa}$

The capacitance is modified as:

$C=\frac{Q}{V} =\kappa\frac{Q_{o}}{V_{o}}=\kappa\ C_{o}$

The stored energy without the dielectric is

$PE_{i}=\frac{1}{2}\frac{Q_{o}^{2}}{C_{o}}=\frac{1}{2}C_{o}V_{o}^{2}$

The stored energy after the dielectric is inserted is:

$PE_{f}=\frac{1}{2}\frac{Q^{2}}{C}=\frac{1}{2}CV^{2}$

If we replace in the above equation the values of V and C we get that

$PE_{f}=\frac{1}{2}\kappa\ C_{o}(\frac{V_{o}}{\kappa})^{2}=\frac{1}{\kappa}(\frac{1}{2}C_{o}V_{o}^{2})$

$PE_{f} =\frac{PE_{i}}{\kappa}$

Finally

$PE_{f} =0.5\ PE_{i}$

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3 years ago

A car passes you at 18 m/s to the north and increases its speed at a rate of 3.0 m/s. Determine the car's velocity when it has a

monitta

122

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2 years ago

Why are not all<br>materials conductive<br>to electricity

Ilia_Sergeevich [38]

Answer:

In conductive materials, the outer electrons in each atom can easily come or go, and are called free electrons. In insulating materials, the outer electrons are not so free to move. All metals are electrically conductive.

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3 years ago