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gtnhenbr [62]
3 years ago
11

The ocean may pull away rom the shore as a tsunami approaches?

Physics
2 answers:
ale4655 [162]3 years ago
6 0
Uh if theres a tsunami it probably will.
Firlakuza [10]3 years ago
4 0
Yes that is what occurs when a tsunami comes
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A bicycle wheel of radius 0.28 m rolls down a hill without slipping. Its linear velocity increases constantly from 0 to 8 m/s in
Marina86 [1]

Answer:

10.989 rad/s²

Explanation:

Angular Acceleration: This is the acceleration of a body that undergoes a circular motion. The S.I unit of angular acceleration is rad/s²

The expression for angular acceleration is given as

a = αr.............. Equation 1

Where a = linear acceleration, α = angular acceleration, r = radius.

make α the subject of the equation

α = a/r............. Equation 2.

But,

a = (v-u)/t ............. Equation 3

Where v = final velocity, u = initial velocity, t = time.

substitute equation 3 into equation 2

α = (v-u)/rt............ Equation 4

Given: v = 8 m/s, u = 0 m/s, r = 0.28 m, t = 2.6 s

Substitute into equation 4

α = (8-0)/(0.28×2.6)

α = 8/0.728

α = 10.989 rad/s²

5 0
3 years ago
A 0.25 kg ideal harmonic oscillator has a total mechanical energy of 9.8 J. If the oscillation amplitude is 20.0 cm, what is the
DanielleElmas [232]

Answer:

7.04 Hz

Explanation:

x(t) = A cos(wt)

v(t) = - wA sin (wt)

Vmax = wA

E = 1/2 * m * (Vmax)^2

E = 1/2*m*(wA)^2

w = \frac{1}{A} \sqrt{\frac{2E}{m} }

f = w/ 2*pi

f = \frac{1}{2*pi*A}*\sqrt{\frac{2E}{m} }  \\f = \frac{1}{2 * pi * 0.2}*\sqrt{\frac{2(9.8)}{0.25} } \\f = 7.04 Hz

6 0
3 years ago
Which of the following waves would produce the loudest sound?
Nezavi [6.7K]

Answer: B

Explanation: the wave with the largest amplitude would create ththe loudest sound, and based on the picture provided, I would guess B has the largest amplitude.

5 0
2 years ago
Read 2 more answers
wink is the seismic station closest to the earthquake. describe two evidences from the seismogram that demonstrates this?
kotykmax [81]

Well, we don't know if it's the CLOSEST one, but it's closer than the other ones on this print-out.

There are actually three clues to this in the seismograms:

1). The waves from the tremor reach the Wink station first ... the P wave gets there 50 seconds before Chicago and 3 whole minutes before Tampa.

2). They are stronger (greater amplitude) at Wink than at Chicago or Tampa.

3). The delay between the P wave and the S wave is the smallest at Wink. This delay between the two waves grows as the detector is farther from the quake.

5 0
3 years ago
The direction of deflection of an electron beam in a magnetic field can be determined by which of the following?
amid [387]

Answer:

Right Hand Rule

Explanation:

When a charged particle travels in a magnetic field, it experiences a force whose magnitude is given by:

F=qvBsin\theta

where

q is the charge of the particle

v is the velocity

B is the magnetic field strength

\theta is the angle between the directions of v and B

The direction of the force can be determined by using the Right Hand Rule, as follows:

- index finger: this should be put in the direction of the velocity

- middle finger: this should be put in the direction of the magnetic field

- thumb: this will give the direction of the force -> however, for a negative charge (as the electron) the direction must be reversed, so it will be opposite.

4 0
3 years ago
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