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zheka24 [161]
4 years ago
5

What are the chances of osteomyelitis one fracture

Physics
1 answer:
Lynna [10]4 years ago
4 0
Depends .. are you having surgery ?
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A light bulb is rated at 25 W when operated at 120 V. How much charge enters (and leaves) the light bulb in 1. 0 min?
aleksklad [387]

The amount of charge enters (and leaves) is 12 Coulomb.

<h3 /><h3>How can we find the value of the amount of charge enters (and leaves)?</h3>

Here we are using the formula,

I=\frac{P}{V} and Q= I \times t

We are given,

P = Power of the light bulb = 25 Watt.

V = The amount of voltage where the light bulb operated = 120 Volt.

t= The time when charge enters (and leaves) the light bulb = 1.0 min = (1 \times 60) second = 60 S

We have to find,

I= The amount of current flows in the light bulb.

Q= The amount of charge enters (and leaves) the light bulb.

Now we substitute the values of known parameters in the first equation, we find that,

I=\frac{P}{V}=\frac{25}{120}

Or, I= 0.20 A

The amount of current flows in the light bulb is 0.20 Ampere.

Now, we put the value of I in the second equation,

Q= I \times t= 0.20 \times 60

Or, Q=12 C

So, from the above calculations we can see that the amount of charge enters (and leaves) the light bulb is 12 Coulomb.

Learn more about the light bulb:

brainly.com/question/8979272

#SPJ4

3 0
2 years ago
1. It’s fall and time for the corn maze and bonfire and you just can’t wait. On your way to the farm though a turkey flies out i
Reptile [31]

Acceleration = (change in velocity ( final speed - starting speed))/ (time)

Acceleration = (18-30)/10.5

Acceleration = -12/10.5

Acceleration = -1.14 m/s^2

Distance = 30m/s x 10.5s + 1/2(1.14)(10.5)^2

Distance = 252.2 meters

8 0
3 years ago
A mercury thermometer has a glass bulb of interior volume 0.100 cm3 at 10°c. the glass capillary 10) tube above the bulb has an
Nadya [2.5K]
Initial volume of mercury is
V = 0.1 cm³

The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.

Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is 
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³

The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
   = (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
   = 4.5 cm

Answer: 4.5 cm
7 0
4 years ago
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A cheetah can run at 30 m/s but only for about 12s. how far will it run in that time
Mashutka [201]
About 360 meters I hope this helps 
6 0
3 years ago
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describe in words the shape of the velocity vs. time graph. how is this related to the shape of the position vs. time graph
Finger [1]

Answer:

CAN YOU PLEASE GIVE ME POINTS???

Explanation:

4 0
3 years ago
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