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katovenus [111]
3 years ago
15

1. A 24.50 g piece of metal displaces 2.6 ml of water. Calculate the density of the metal?

Chemistry
2 answers:
arsen [322]3 years ago
7 0

Answer:

\rho =9.42g/mL

Explanation:

Hello,

In this case, this is an example of Archimedes principle in which we can compute the density of metal by means of the displaced volume a mass does, in this case, 24.50 g displaced 2.6 mL of water, thus, the density turns out:

\rho =\frac{m}{V}=\frac{24.50g}{2.6mL}\\  \\\rho =9.42g/mL

Best regards.

PSYCHO15rus [73]3 years ago
3 0

Answer:

9.42g/cm3

Explanation:

Data obtained from the question include the following:

Mass of the metal = 24.50g

Volume of metal = 2.6 ml = 2.6cm3

Density =..?

The density of a substance is defined by the mass of the substance per unit volume of the substance. It is represented mathematically as:

Density = Mass /volume

With the above formula, we can obtain the density of the metal as follow:

Density = Mass/volume

Density = 24.50g/2.6cm3

Density = 9.42g/cm3

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pitch

Explanation:

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Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n
natta225 [31]

Answer: Mass Of CFC that needs to evaporate for the freezing of water = 328.24 g

Explanation: Heat gained by the CFC = Heat lost by water

Heat lost by water = Heat required to take water's temperature to 0°c + Heat required to freeze water at 0°c

Heat required to take water's temperature from 33°c to 0°c = mCΔT

m = 201g, C = 4.18 J/(gK), ΔT = 33

mCΔT = 201 × 4.18 × 33 = 27725.94 J

Heat required to freeze water at 0°c = mL

m = 201g, L = 334 J/g

mL = 201 × 334 = 67134 J

Heat gained by CFC to vaporize = mH = 27725.94 + 67134 = 94859.94 J

H = 289 J/g, m = ?

m × 289 = 94859.9

m = 328.24 g

QED!!

7 0
3 years ago
Describe the PURPOSE of Moh's hardness scale. (What information does it tell you)
Lerok [7]

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Explanation: Hope this helped! :)

6 0
3 years ago
A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
Tasya [4]

\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of \sf{CaCO_3}

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

3 0
3 years ago
Read 2 more answers
In the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reas
Alexus [3.1K]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.

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