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maxonik [38]
2 years ago
7

Compute the number of games using the formula of “SINGLE ROUND ROBIN” and plot the games in a table:

Engineering
1 answer:
Bogdan [553]2 years ago
3 0

Answer:

N=27.02

Explanation:

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The wet density of a sand was found to be 1.9 Mg/m3 and the field water content was 10%. In the laboratory, the density of solid
Nookie1986 [14]

Answer:

a) 44.4%

b) 72 mm

Explanation:

See attached pictures.

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If you are convicted of D.U.I. a second time in five years, your license may be revoked for up to __________ year/s.
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If you are convicted of a dui for a second time in five years, your license may be revoked for up to (2) years
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The Accenture team is involved in helping a client in the transformation journey using Cloud computing. How is myNav beneficial
professor190 [17]

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It helps ensure the security of client data.

Explanation:

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8 0
2 years ago
An approach to a signalized intersection has a saturation flow rate of 1800 veh/h. At the beginning of an effective red, there a
Tcecarenko [31]

Answer: The total vehicle delay is

39sec/veh

Explanation: we shall define only the values that are important to this question, so that the solution will be very clear for your understanding.

Effective red time (r) = 25sec

Arrival rate (A) = 900veh/h = 0.25veh/sec

Departure rate (D) = 1800veh/h = 0.5veh/sec

STEP1: FIND THE TRAFFIC INTENSITY (p)

p = A ÷ D

p = 0.25 ÷ 0.5 = 0.5

STEP 2: FIND THE TOTAL VEHICLE DELAY AFTER ONE CYCLE

The total vehicle delay is how long it will take a vehicle to wait on the queue, before passing.

Dt = (A × r^2) ÷ 2(1 - p)

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4 0
3 years ago
A reciprocating compressor takes a compresses it to 5 bar. Assuming that the compression is reversible and has an index, k, of 1
Gelneren [198K]

Answer:

final temperature is 424.8 K

so correct option is e 424.8 K

Explanation:

given data

pressure p1 = 1 bar

pressure p2 = 5 bar

index k = 1.3

temperature t1 = 20°C = 293 k

to find out

final temperature  t2

solution

we have given compression is reversible and has an index k

so we can say temperature is

\frac{t2}{t1}= [\frac{p2}{p1}]^{\frac{k-1}{k} }  ...........1

put here all these value and we get t2

\frac{t2}{293}= [\frac{5}{1}]^{\frac{1.3-1}{1.3} }

t2 = 424.8

final temperature is 424.8 K

so correct option is e

5 0
3 years ago
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