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loris [4]
3 years ago
10

Early cameras were little more than a box with a pinhole on the side opposite the film. (a) What angular resolution would you ex

pect from a pinhole with a 0.50-mm diameter? (b) What is the greatest distance from the camera at which two point objects 15 cm apart can be resolved? (Assume light with a wavelength of 520 nm.
Physics
1 answer:
ollegr [7]3 years ago
3 0

Answer:

angular resolution = 0.07270° = 1.269 × 10^{-3} rad

greatest distance from the camera = 118.20 m = 0.118 km

Explanation:

given data

diameter = 0.50 mm = 0.5 × 10^{-3} m

distance apart = 15 cm =  15× 10^{-2} m

wavelength λ = 520 nm = 520 × 10^{-9} m

to find out

angular resolution and greatest distance from the camera

solution

first we expression here angular resolution that is

sin θ = \frac{1.22* \lambda }{D}   .......................1

put here value λ is wavelength and d is diameter

we get

sin θ = \frac{1.22*520*10^{-9}}{0.5*10^{-3}}

θ = 0.07270° = 1.269 × 10^{-3} rad

and

distance from camera is calculate here as

θ = \frac{I}{r}    .................2

I = \frac{15*10^{-2}}{1.269*10^{-3}}

I = 118.20 m = 0.118 km

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makkiz [27]

Explanation:

Given parameters:

Distance  = 180m

Time  = 12s

Unknown:

Speed  in m/s and km/hr

Solution:

Speed is the distance divided by the time taken,

   Speed  = \frac{distance}{time}  

So;

     Speed  = \frac{180}{12}   = 15m/s

   1000m = 1km

  3600s  = 1hr

Therefore;

   15 x m x \frac{1}{s}  x \frac{1km}{1000m} x \frac{3600s}{1hr}    = 54km/hr

5 0
3 years ago
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance x from the 50
Rom4ik [11]

Answer:

x=0.01457 m

Explanation:

From parallel axis theorem

I=Icm+mh²

where h=x

The rotational inertia about its center of mass is

Icm=mL²/12

where L=1.0 m

Thus T=4.8s  we obtain

T=2\pi \sqrt{\frac{mL^{2}/12+mx^{2}  }{mgx} }\\ T=2\pi \sqrt{\frac{L^{2} }{12gx}+x/g }\\ T^{2}=4\pi^{2}(\frac{L^{2} }{12gx}+x/g )/x\\ T^{2}x=\frac{\pi^{2} L^{2} }{3g}+(\frac{4\pi^{2} }{g})x^{2}\\   0=(\frac{4\pi^{2}  }{g} )x^{2}-(T^{2} )x+(\frac{\pi^{2}L^{2}   }{3g} )\\ 4.03x^{2}-23.04x+0.335=0

After Solving this quadratic we get

x₁=5.702 m

x₂=0.01457 m

One of the solution is an impossible value for x (x=5.70m is greater than L)

So we choose the other one

x=0.01457 m

3 0
4 years ago
A scientific hypothesis can become a theory if
viktelen [127]

Answer: If, enough evidence accumulates to support a hypothesis, it moves to the next step (known as a theory) in the scientific method and becomes accepted as a valid explanation of a phenomenon.

Explanation:  a scientific theory is the framework for observations and facts.

( hope this helped )

5 0
3 years ago
The volume of a gas at 59.0kPa is 600ml. if the pressure is increase to 138.0kPa, what will be the new volume?
likoan [24]

Answer:

<h3>The answer is 256.52 mL</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{59000 \times 600}{138000}  =  \frac{35400000}{138000}  \\  = 256.521739...

We have the final answer as

<h3>256.52 mL</h3>

Hope this helps you

4 0
3 years ago
A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
3 years ago
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