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Jlenok [28]
2 years ago
13

Estimate the average rate of change in elevation from d to points i, ii, and iii, assuming the distance from d to i is 3500 m, t

he distance from d to ii is 2500 m, the distance from d to iii is 1250 m. (assume that each point lies on a contour line. round your answers to two decimal places.)
Physics
1 answer:
Anit [1.1K]2 years ago
8 0
Ummm i am not going to be able say i am high

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What is the velocity of a ball dropped from a height of 150 m when it hits the ground? Take the upward direction as positive.
djyliett [7]

Answer:

The velocity of the ball when its hit the ground will be 54.22 m/sec    

Explanation:

We have given height from which ball is dropped h = 150 m

Acceleration due to gravity g=9.8m/sec^2

As the ball is dropped so initial velocity will be zero so u = 0 m/sec

According to third equation of motion we know that v^2=u^2+2gh

v^2=0^2+2\times 9.8\times 150

v=54.22m/sec

So the velocity of the ball when its hit the ground will be 54.22 m/sec

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Explanation:

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In a 200-turn automobile alternator, the magnetic flux in each turn is ΦB = 2.50 10-4 cos ωt, where ΦB is in webers, ω is the an
n200080 [17]

Answer:

10.63952sin(209.43951t)

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Explanation:

N_t = Number of turns = 200

\phi_B = Magnetic flux = 2.5\times 10^{-4}cos(\omega t)

\omega_e = Engine angular speed = 1\times 10^{3}\ rpm

Alternator angular speed is given by

N_a=2\times \omega_e\\\Rightarrow N_a=2\times 1\times 10^{3}\\\Rightarrow N_a=2\times 10^{3}\ rpm

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Induced emf is given by

\epsilon=-N_t\dfrac{d\phi_B}{dt}\\\Rightarrow \epsilon=-200\dfrac{d}{dt}2.54\times 10^{-4}cos(209.43951 t)\\\Rightarrow \epsilon=200\times 2.54\times 10^{-4}\times 209.43951 sin(209.43951t)\\\Rightarrow \epsilon=10.63952sin(209.43951t)

The function is 10.63952sin(209.43951t)

The induced maximum emf is 10.63952 V

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