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tankabanditka [31]
2 years ago
4

Three different experiments are conducted that pertain to the oscillatory motion of a pendulum. For each experiment, the length

of the pendulum and the mass of the pendulum are indicated. In all experiments, the pendulum is released from the same angle with respect to the vertical. If the students collect data about the kinetic energy of the pendulum as a function of time for each experiment, which of the following claims is true?
a. The data collected from Experiment 1 will be the same as the data collected from Experiment 2.
b. The data collected from Experiment 1 will be the same as the data collected from Experiment 3.
c. The data collected from Experiment 2 will be the same as the data collected from Experiment 3.
d. The data collected from each experiment will be different.
Physics
1 answer:
ryzh [129]2 years ago
0 0

Answer:

d. The data collected from each experiment will be different.

Explanation:

The time period of simple pendulum depends on length of pendulum and independent of mass of pendulum.

For three experiments data is collected. Kinetic energy depends on mass and square of velocity.

SO FOR THREE EXPERIMENTS THE DATA COLLECTED WILL BE DIFFERENT.

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Two speakers placed 0.94 m apart produce pure tones in sync with each other at a frequency of 1630 Hz. A microphone can be moved
Alina [70]

Answer:

a. approximately 1.1\; \rm m (first minimum.)

b. approximately 2.2\; \rm m (first maximum.)

c. approximately 3.4\; \rm m (second minimum.)

d. approximately 4.7\; \rm m (second maximum.)

Explanation:

Let d represent the separation between the two speakers (the two "slits" based on the assumptions.)

Let \theta represent the angle between:

  • the line joining the microphone and the center of the two speakers, and
  • the line that goes through the center of the two speakers that is also normal to the line joining the two speakers.

The distance between the microphone and point P_0 would thus be 9.4\, \tan(\theta) meters.

Based on the assumptions and the equation from Young's double-slit experiment:

\displaystyle \sin(\theta) = \frac{\text{path difference}}{d}.

Hence:

\displaystyle \theta = \arcsin \left(\frac{\text{path difference}}{d}\right).

The "path difference" in these two equations refers to the difference between the distances between the microphone and each of the two speakers. Let \lambda denote the wavelength of this wave.

\displaystyle \begin{array}{c|c} & \text{Path difference} \\ \cline{1-2}\text{First Minimum} & \lambda / 2 \\ \cline{1-2} \text{First Maximum} & \lambda \\\cline{1-2} \text{Second Minimum} & 3\,\lambda / 2 \\ \cline{1-2} \text{Second Maximum} & 2\, \lambda\end{array}.

Calculate the wavelength of this wave based on its frequency and its velocity:

\displaystyle \lambda = \frac{v}{f} \approx 0.211\; \rm m.

Calculate \theta for each of these path differences:

\displaystyle \begin{array}{c|c|c} & \text{Path difference} & \text{approximate of $\theta$} \\ \cline{1-3}\text{First Minimum} & \lambda / 2 & 0.112 \\ \cline{1-3} \text{First Maximum} & \lambda & 0.226\\\cline{1-3} \text{Second Minimum} & 3\,\lambda / 2 & 0.343\\ \cline{1-3} \text{Second Maximum} & 2\, \lambda & 0.466\end{array}.

In each of these case, the distance between the microphone and P_0 would be 9.4\, \tan(\theta). Therefore:

  • At the first minimum, the distance from P_0 is approximately 1.1\; \rm m.
  • At the first maximum, the distance from P_0 is approximately 2.2\; \rm m.
  • At the second minimum, the distance from P_0 is approximately 3.4\; \rm m.
  • At the second maximum, the distance from P_0 is approximately 4.7\;\rm m.
6 0
2 years ago
Mass of 55 kg riding in a car at20m/s slams on brakes rests in.5 sec how much force from seatbelt
Evgen [1.6K]
2,200 Newtons.

F = ma

v f = v i + at
0mls = 20mls + a(.5s)

-20mls/.5s = -40mls squared

-40mls squared (55kg) = 2,200 Newtons.

Hope this helps!
5 0
2 years ago
The is the sac-like structure that holds the testes.
Brilliant_brown [7]

Answer:

Scrotum

Explanation:

5 0
2 years ago
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15 points!!!
AfilCa [17]
Use google cuz google is most intelligent than us


-Just sayin don’t get mad
5 0
1 year ago
As demonstrated by the Doppler Effect, why does sound increase in pitch as a sound source approaches you?
scZoUnD [109]
I think so it ans wold be d.because if the source approaches the observer more and more wavefront will pass and it get squeezed.so wavelength decreases and frequency increases.
3 0
1 year ago
Read 2 more answers
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