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Tomtit [17]
3 years ago
13

Identify the compound with the highest standard free energy of formation. identify the compound with the highest standard free e

nergy of formation. no(g)
Chemistry
1 answer:
Anestetic [448]3 years ago
7 0
The compound with the highest standard free energy of formation is O3(g)


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At 25 ∘C the reaction CaCrO4(s)←→Ca2+(aq)+CrO2−4(aq) has an equilibrium constant Kc=7.1×10−4. What is the equilibrium concentrat
Nitella [24]

Answer:

2.67 × 10⁻²

Explanation:

Equation for the reaction is expressed as:

CaCrO₄(s)    ⇄      Ca₂⁺(aq)         +        CrO₂⁻⁴(aq)

Given that:

Kc=7.1×10⁻⁴

Kc= [Ca^{2+}][CrO^{2-}_4]

Kc= [x][x]

Kc= [x²]

7.1×10⁻⁴ =  [x²]

x = \sqrt{7.1*10^{-4}}

x = 0.0267

x = 2.67*10^{-2}

6 0
3 years ago
Which term describes the molecule shown below h-c-c-h ethyne c2h2?
Andru [333]
Ethyne also known as Acetylene and is the simplest Alkyne belonging to  Unsaturated Hydrocarbons. It contains triple bond between two carbon atoms in a molecule. Carbon atoms in Acetylene are sp Hybridized and has a linear shape with bond angle of 180° is present between C-C-H bonds. This compound is also called as Binary Compound because it is made up of two elements i.e. Carbon and Hydrogen. The terminal Hydrogen in Acetylene is slightly Acidic in nature, and this compound can donate terminal proton to any strong base. These compounds generally give Electrophillic Addition Reactions.
4 0
3 years ago
Read 2 more answers
Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0
3 years ago
The unheated Gas in the above system has a volume of 20.0 L at a temperature of 25.0 C and a pressure of 1.00 atm. The gas is he
kipiarov [429]

Answer:

1.25 atm.

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 20L

Initial temperature (T1) = 25°C

Initial pressure = 1 atm

Final temperature (T2) = 100°C

Final volume (V2) = constant i.e remain the same

Final pressure (P2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below:

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 25°C = 25°C + 273 = 298K

Final temperature (T2) = 100°C = 100°C + 273 = 373K

Step 3:

Determination of the final pressure of the gas. This is illustrated below:

Since the volume is constant, the following equation, P1/T1 = P2/T2 will be used to obtain the final pressure of gas as follow:

P1/T1 = P2/T2

Initial temperature (T1) = 298k

Initial pressure = 1 atm

Final temperature (T2) = 373K

Final pressure (P2) =?

P1/T1 = P2/T2

1/298 = P2 /373

Cross multiply to express in linear form

298 x P2 = 1 x 373

Divide both side by 298

P2 = 373/298

P2 = 1.25 atm.

Therefore, the pressure of the heated gas is 1.25 atm.

3 0
3 years ago
Convert 120 degrees F to K.<br> [?]K
hram777 [196]
120 Fahrenheit -32 x 5/9 +273.15 = 322
3 0
3 years ago
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