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3 years ago

13

Identify the compound with the highest standard free energy of formation. identify the compound with the highest standard free e

nergy of formation. no(g)

1 answer:

Anestetic [448]3 years ago

7 0

The compound with the highest standard free energy of formation is O3(g)

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The PRODUCT is found on the right side of the arrow in a chemical reaction.

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3 years ago

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What is the chemical formula for 8.6 mol of sulfur and 3.42 mol of phosphorus

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The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅

<h3>How do I determine the formula of the compound?</h3>

From the question given above, the following data were obatined:

Sulphur (S) = 8.6 moles
Phosphorus (P) = 3.42 mole
Chemical formula =?

The chemical formula of the compound can be obtained as follow:

Divide by their molar mass

S = 8.6 / 32 = 0.26875

P = 3.42 / 31 = 0.11032

Divide by the smallest

S = 0.26875 / 0.11032 = 2.44

P = 0.11032 / 0.11032 = 1

Multiply by 2 to express in whole number

S = 2.44 × 2 = 5

P = 1 × 2 = 2

Thus, the chemical formula is P₂S₅

Learn more about empirical formula:

brainly.com/question/9459553

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5 0

1 year ago

A sample of a compound of xenon and fluorine contains molecules of a single type; XeFn, where n is a whole number. If 5.0 x 1020

kicyunya [14]

Answer:

4

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by $N_0$ .

Also, it is the number of particles in exactly 12.000 g of isotope carbon 12.

Avogadro constant:-

$N_a=6.023\times 10^{23}$

Hence,

Mass of $XeF_n$ = 131.293+ n18.998 g

So,

$6.023\times 10^{23}$ molecules have a mass of 131.293+ n18.998 g

Also,

$1$ molecules have a mass of $\frac{(131.293+ n18.998)}{6.023\times 10^{23}}$ g

So,

$5.0\times 10^{20}$ molecules have a mass of $\frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20}$ g

Also, given mass = 0.172 g

Thus,

$\frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20}=0.172$

$\frac{18.998n+131.293}{1204.6}=0.172$

$18.998n+131.293=207.1912$

$n=\frac{75.8982}{18.998}=4$

<u>Thus, value of n is 4.</u>

4 0

2 years ago