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ella [17]
3 years ago
5

A student measured the specific heat of water to be 4.29 J/g.Co. The

Physics
1 answer:
leonid [27]3 years ago
7 0

Answer:

2.63 %.

Explanation:

Given that,

The calculated value of the specific heat of water is 4.29 J/g.C

Original value of  specific heat of water is 4.18 J/g.C.

We need to find the student's percent error. The percentage error in any quantity is given by :

P=\dfrac{|\text{original value-calculated value}|}{\text{original value}}\times 100\\\\P=\dfrac{4.29-4.18}{4.18}\times 100\\\\P=2.63\%

So, the student's percent error is 2.63 %.

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What best explains why a wood burning fire place represents an open system
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Answer:

Because it is open to more wood being burned and it is giving smoke out

Explanation:

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A 1400-kg car moving with a speed of 32 m/s is approaching a stoplight. The light turns yellow and the car makes an abrupt stop
inna [77]

Answer:

c. 716, 800 J

Explanation:

t = Time taken

u = Initial velocity = 32 m/s

v = Final velocity = 0

s = Displacement = 60 m

a = Acceleration

m = Mass of car = 1400 kg

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-32^2}{2\times 60}

Work done is given by

W=Fscos\theta\\\Rightarrow W=mascos\theta\\\Rightarrow W=1400\times \dfrac{0^2-32^2}{2\times 60}\times 60\times cos0\\\Rightarrow W=-716800\ J

The amount of work done to stop the car is 716800 J

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3 years ago
All EM waves (light waves) travel at the same speed through the vacuum of space. If the different types of waves are distinguish
Rudiy27
I don’t know the answer i just need the points
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3 years ago
A force of 3600 N is exerted on a piston that has an area of 0.030 m2. What force is exerted on a second piston that has an area
Airida [17]
For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
p_1 = p_2
which becomes
\frac{F_1}{A_1}= \frac{F_2}{A_2}
where
F_1=3600 N is the force on the first piston
A_1=0.030 m^2 is the area of the first piston
F_2 is the force on the second piston
A_2=0.015 m^2 is the area of the second piston

If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
F_2=F_1  \frac{A_2}{A_1}=(3600 N) \frac{0.015 m^2}{0.030 m^2}= 1800 N
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3 years ago
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1. A runner has an initial speed of 2 [m/s] and slowly speeds up with a constant acceleration of
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Answer:

Final Velocity = 4.9 m/s

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We are given;. Initial velocity; u = 2 m/s

Constant Acceleration; a = 0.1 m/s²

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To find the final velocity(v), we will use one of Newton's equations of motion;

v² = u² + 2as

Plugging in the relevant values to give;

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3 years ago
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