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FromTheMoon [43]
3 years ago
10

What types of gas molecules typically diffuse and effuse faster?

Chemistry
1 answer:
JulijaS [17]3 years ago
5 0
Lighter gases (in weight) diffuse and Effuse faster than heavier gases.
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In the lab, you are given a metal ball. You measure the mass of the ball to be 28 g. You place the ball in a graduated cylinder
KIM [24]

Answer:

Density = 8.75ml

Explanation:

Density = Mass / Volume

In this problem ...

Mass = 28 grams

Volume = 31.4ml - 28.2ml = 32ml (water displacement also)

∴Density = mass /volume = 28g/32ml = 8.75g/ml

8 0
3 years ago
Which of the following is physical change!?
Lemur [1.5K]
<h2>_______________________</h2><h2 /><h2 /><h2>D - All of The Above</h2>

<h3>Dissolve:</h3>

To Become or cause to become incorporated into a liquid so as to form a solution.

<h3>Evaporation:</h3>

The process of changing from liquid to vapour.

<h3>Bending:</h3>

To shape or force something straight, in a curve or angle.

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6 0
3 years ago
Plz help. I just need someone to check answer. :(
My name is Ann [436]
These substances can be separated by distillation, so your answer is A.
5 0
3 years ago
Which component is missing from the process of photosynthesis? Carbon Dioxide + Water + _________ → Glucose + Oxygen Group of an
telo118 [61]

Answer:

Sunlight

Explanation:

Photosynthesis is the process where by plants manufacture their own food through conversion of carbon(iv)oxide and water in presence to sunlight to produce glucose and oxygen as by product.

The reaction is photo-catalyzed and would only take place in the presence of sunlight.

6CO₂ + 6H₂O + sunlight → C₆H₁₂O₆ + 6O₂

4 0
3 years ago
Read 2 more answers
When a student chemist transferred the metal to the calorimeter, some water splashed out of the calorimeter. will this technique
Natalka [10]

Answer:

It will be reported too low.

Explanation:

To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.

Qmetal + Qwater = 0

Qmetal = -Qwater

The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:

m_metal*s*ΔT_metal = - m_water *c*ΔT_water

s = -m_water *c*ΔT_water / m_metal*ΔT_metal

So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.

5 0
3 years ago
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