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3 years ago

*Name three ways the organisms in a food web get energy.

Chemistry

1 answer:

Anuta_ua [19.1K]3 years ago

6 0

Answer:

1.)photosynthesis, chemosynthesis, and the consumption, this is three ways how organisms in a food web gets energy.

2.)Cells use energy in order to grow, regulate metabolism and reproduce. This energy is obtained from a source such as food molecules or light from the sun, and through processes like glycolysis, the citric acid cycle and oxidative phosphorylation, an energy-rich molecule is then created. The cell can then use the energy in the protein molecule to help it function.

3.)Food webs vary according to habitat, but all food webs have some things in common. Primary producers make up the base of a food web. Phytoplankton . Consumers cannot make their own food so they need to get food from other sources. This means that we are close to being a consumer because we cant make up our own food and we have to get other food from animals and plants and our drinks from many things that go through the food web.

Explanation:

You might be interested in

Which of the following pairs of elements would most likely combine to form a salt?

Gnom [1K]

I think it’s Ca and Cs

8 0

3 years ago

Inclined planes reduce the amount of effort needed to move an object, but increases

QveST [7]

Inclined planes reduce the amount of effort needed to move an object, but increases the length of the ramp.

<u>Explanation:</u>

Mechanical advantage is the measure of amount of effort needed to move an object. The mechanical advantage can be calculated as the ratio of length of ramp to the height of ramp for an inclined plane.

As it is known that an object can be easily moved on an inclined plane than on a vertical plane, this is because, the inclined plane provides greater output force. But in that case, the effort required will be reduced with the cost of increasing the distance of the movement of object.

In other terms , the ramp's length of inclined planes has to get increased in order to reduce the amount of effort needed to move an object. This is because as the mechanical advantage has length of the ramp in the numerator, with the increase in numerator value or length value the mechanical advantage will also increase.

8 0

4 years ago

25. How many ml of a .0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid?

Mariana [72]

Answer: There are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Explanation:

Given: $M_{1}$ = 0.0023 M, $V_{1}$ = ?

$V_{2}$ = 15.0 mL, $M_{2}$ = 0.012 M

Formula used to calculate volume of strontium hydroxide solution is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.0023 M \times V_{1} = 0.012 M \times 15.0 mL\\V_{1} = 78.26 mL$

Thus, we can conclude that there are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

8 0

3 years ago

A) Calculate the osmotic pressure difference between seawater and fresh water. For simplicity, assume thatall the dissolved salt

never [62]

Answer:

a) Δπ = 1.264 atm

b) W = 128 joules

c) ΔH >> W ( a factor greater than 17,000 )

Explanation:

a) The osmotic pressure, π , is determined by :

π = nRT/V, where n= moles of solute

R= 0.0821 Latm/kmol

T = 300 K

calling π(sw) osmotic pressure for for sea water and π (fw) for fresh water,

salinity of sea water = 3.5 g / 1L water (assuming only NaCl for the salts)

salinity of fresh water = 0.5 parts per thousand (range: 0- 0.5 ppt)

πsw = (3.5 g/58.44 g/mol) (0.0821 Latm/Kmol) (300 K ) /1 L = 1.475 atm

πfw = (0.5 g/58.44 g/mol) (0.0821 Latm/Kmol) (300 K ) /1 L = 0.211 atm

d water = 1 g/cm³

Δ π = (1.475 - 0.211) = 1.264 atm

b) W = Δπ V = 1.426 atm x 1L = 1.43 L-atm

1 L-atm = 101.33 j

W = 101.33 j/ Latm x 1.43 Latm = 128 joules

c) ΔH = Q₁ + nΔH vap, where

Q₁ = heat required to bring the solution from 300 K to boiling, 373 K

ΔH vap = heat of vaporization

Q = mCΔT = 1000 g x 4.186 j x 73 K = 305.6 j = 0.3056 kj

ΔH vap = (1000 g/ 18 g/mol ) 40.7 kj/mol = 2,261 kj

ΔH = 0.3056 kj + 2,261 kj = 2,261.3 kj

Note = Q << ΔH vap and we could have neglected it.

This result shows why nobody talks about evaporation of sea water to produce fresh water ΔH >> W

6 0

3 years ago

A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At

Mazyrski [523]

According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

P</span>₁ / T₁ = P₂ / T₂ ----- (1)
Data Given;
P₁ = 1.5 atm

T₁ = 35 °C + 273 = 308 K

P₂ = ?

T₂ = 0 °C + 273 = 273 K

Solving Eq. 1 for P₂,

P₂ = P₁ T₂ / T₁

Putting values,
P₂ = (1.5 atm × 273 K) ÷ 308 K

P₂ = 1.32 atm
Result:
As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.

5 0

3 years ago