QUICK ANSWER
The collision between two gas molecules or billiard balls can be approximated as elastic collisions. Elastic collisions are exchanges of kinetic energy between two bodies having different reference frames in which the total kinetic energy of the two bodies after collision is equal to the energy before collision.'
Answer:
P₁ = 219.3 Pa
Explanation:
This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.
Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.
P₁ = P₂
pressure is defined by
P = F / A
we subtitute
F₁ / A₁ = F₂ / A₂
F₁ = F₂ A₁ / A₂
the area in a circle is
A = π r² = π d² / 4
we substitute
F₁ = F₂ (d₁ / d₂)²
we calculate
F₁ = 17640 (2/32)²
F₁ = 68.9 N
Having the force to be applied we can find the air pressure on the small plunger
P₁ = F₁ / A₁
P₁ = F₁ 4 / π d₁²
let's calculate
P₁ = 68.9 4 / (π 0.02²)
P₁ = 219.3 Pa
Work = Force * distance
W = Fd
Given F = 500 N, d = 10 m
W = (500)(10)
W = 5000 J
The work done is 500 Joules. The time of 4 s is irrelevant in this case.
Answer:
In an inductive circuit, when frequency increases, the circuit current decreases and vice versa.
Explanation:
