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Lilit [14]
3 years ago
11

A 0.784 g sample of magnesium is added to a 250 ml flask and dissolved in 150 ml of water. magnesium hydroxide obtained from the

reaction required 215.0 ml of 0.300 m hydrochloric acid to completely react. how many moles of hcl were used?
Chemistry
1 answer:
V125BC [204]3 years ago
4 0

A lot of values are given but we must focus only on HCl.

<span>There are 215 mL (0.215 L) of 0.300 M HCl that was completely   used. We must remember the moles is simply the product of volume and molarity, that is:</span>

 

number of moles = 0.215 L * 0.300 M

<span>number of moles= 0.0645 moles HCl</span>

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4. A 14.5-L balloon is in the air where it is 20.0 C at 0.980-atm. A wind passes over and the balloon's pressure becomes 740.0-m
jeka94

The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

<h3>What is Combined gas law?</h3>

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 14.5L
  • Initial pressure P₁ = 0.980atm
  • Initial temperature T₁ = 20.0°C = 293.15K
  • Final volume V₂ = 14.3L
  • Final pressure P₂ = 740.mmHg = 0.973684atm
  • Final temperature T₂ = ?

We substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂

14.21Latm / 293.15K = 13.92368Latm / T₂

14.21Latm × T₂ = 13.92368Latm × 293.15K

14.21Latm × T₂ = 4081.72679LatmK

T₂ = 4081.72679LatmK / 14.21Latm

T₂ = 287.24K

T₂ = 14.09°C

Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

Learn more about the combined gas law here: brainly.com/question/25944795

#SPJ1

4 0
2 years ago
The combustion of 0.590 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
Alenkinab [10]

Answer:

2.943 °C temperature change from the combustion of the glucose has been taken place.

Explanation:

Heat released on combustion of Benzoic acid; :

Enthaply of combustion of benzoic acid = 3,228 kJ/mol  

Mass of benzoic acid = 0.590 g

Moles of benzoic acid = \frac{0.590 g}{122.12 g/mol}=0.004831 mol

Energy released by 0.004831 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004831 mol=15.5955 kJ=15,595.5 J

Heat capacity of the calorimeter = C  

Change in temperature of the calorimeter = ΔT = 2.125°C

Q=C\times \Delta T

15,595.5 J=C\times 2.125^oC

C=7,339.05 J/^oC

Heat released on combustion of Glucose: :

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=1.400 g

Moles of glucose =\frac{1.400 g}{180.16 g/mol}=0.007771 mol

Energy released by the 0.007771 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.007771 mol=21.6030 kJ=21,603.01 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

21,603.01 J=7,339.05 J/^oC\times \Delta T'

\Delta T'=2.943^oC

2.943 °C temperature change from the combustion of the glucose has been taken place.

8 0
3 years ago
The periodic table of elements is organized by the number of
skelet666 [1.2K]

Answer:

the increasing mass number

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2 years ago
Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.
Pie
3024.75 Joules needed to warm iron
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3 years ago
What is the use of a pedigree chart? Please do not answer wat a perigee chart is!.
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Pedigree charts are used to see traits that are present in families or individuals. For example, it can be used see if certain diseases are running through someone's family and if that individual will inherit the disease.
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3 years ago
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