g Four primary sedimentation basins are designed for total average flow of 1.2 m3/s. The TSS concentration in the primary treate
d effluent is 150 mg/L, and TSS removal is 63 percent. The sludge has an average solids concentration of 6 percent and specific gravity of 1.045. What is the capacity of the sludge pump in m3/min per basin if the pump is used on a 15-min pumping cycle per h
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Answer:
4m/s
Explanation:
We know that power supplied by the motor should be equal to the rate at which energy is increased of the mass that is to be hoisted
Mathematically
\
We also know that Power = force x velocity ..................(i)
The force supplied by the motor should be equal to the weight (mg) of the block since we lift the against a force equal to weight of load
=> power = mg x Velocity........(ii)
While hoisting the load at at constant speed only the potential energy of the mass increases
Thus Potential energy = Mass x g x H...................(iii)
where
g = accleration due to gravity (9.81m/s2)
H = Height to which the load is hoisted
Equating equations (ii) and (iii) we get
m x g x v =
thus we get v = H/t
Applying values we get
v = 6/1.5 = 4m/s