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gregori [183]
3 years ago
12

A particle accelerates from rest at 5.7 m/s 2 . what is its speed 7.2 s after the particle starts moving? answer in units of m/s

.
Physics
1 answer:
True [87]3 years ago
6 0
It starts from rest meaning the initial velocity is 0

is accelerates at 5.7m/s^2 meaning a = 5.7m/s^2

t = 7.2s

vf = vi + at 

vf = final velocity
vi = initial velocity 
a = acceleration 
t = time 

we are looking for the final velocity 

vf = vi + at 

vf = 0 + (5.7 * 7.2)

vf = 41.04 m/s  -------This is your answer


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3 years ago
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Blizzard [7]

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Difference threshold or also Just Noticeable Difference

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7 0
3 years ago
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docker41 [41]

Answer:

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