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gregori [183]
4 years ago
12

A particle accelerates from rest at 5.7 m/s 2 . what is its speed 7.2 s after the particle starts moving? answer in units of m/s

.
Physics
1 answer:
True [87]4 years ago
6 0
It starts from rest meaning the initial velocity is 0

is accelerates at 5.7m/s^2 meaning a = 5.7m/s^2

t = 7.2s

vf = vi + at 

vf = final velocity
vi = initial velocity 
a = acceleration 
t = time 

we are looking for the final velocity 

vf = vi + at 

vf = 0 + (5.7 * 7.2)

vf = 41.04 m/s  -------This is your answer


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Water is boiling in a clear pot, as shown in the picture. Which takes place as water cycles from the bottom of the pot toward th
nikitadnepr [17]

Hot and cold water rising and sinking through other water
is definitely a description of convection.
6 0
4 years ago
Read 2 more answers
When an object such as a plastic comb is charged by rubbing it with a cloth, the net charge is typically a few microcoulombs. If
masya89 [10]

The concept required to solve this problem is quantization of charge.

First the number of electrons will be calculated and then the total mass of the charge.

With these data it will be possible to calculate the percentage of load in the mass.

Q= ne

Here Q is the charge, n is the number of electrons and e is the charge on the electron

n = \frac{Q}{e}

Replacing,

n = \frac{4*10^{-6}C}{1.6*10^{-19}}

n = 2.5 * 10^{13}77

According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron

The total mass of the charge is

m= nm_e

Here,

m = Mass of the charge

n = Number of electrons

m_e = Mass of the electron

\text{Percentage change} = \frac{nm_e}{M}*100

Replacing we have

\text{Percentage change} = \frac{(2.5*10^13)(9.1*10^{-28})}{33}*100

\text{Percentage change} = 6.9*10^{-14} \%

6 0
4 years ago
The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 3.6 N and the angl
Nuetrik [128]
<h3>Answer</h3>

6.6 N pointing to the right

<h3>Explanation</h3>

Given that,

two forces acting of magnitude 3.6N

angle between them = 48°

To find,

the third force that will cause the object to be in equilibrium

<h3>1)</h3>

Find the vertical and horizontal components of the two forces

vertical force1 = sin(24)(3.6)

vertical force2= -sin(24)(3.6)

<em>(negative sign since it is acting on opposite direction)</em>

vertical force3 = sin(24)(3.6) - sin(24)(3.6)

                        = 0

<h3>2)</h3>

horizontal force1 = cos(24)(3.6)

horizontal force2= cos(24)(3.6)

horizontal force3 = cos(24)(3.6) + cos(24)(3.6)

                            = 2(cos(24)(3.6))

                            = 6.5775 N

                            ≈ 6.6 N

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4 0
4 years ago
Moving by short leaps on one foot at a time.
Evgen [1.6K]

The answer is:

Hopping.

Explanation:

Hopping is done by taking off on one foot and landing back on that same foot. Hopping is done in shorter intervals, meaning you usually don't travel large distances through a single hop. Hopping is categorized as short leaps for its small distance covered singularly, and each hop is done only on one foot.

<em>(Think about if one of your feet/legs is injured or asleep. If you wanted to go from say the living room to the kitchen, but didn't wish to move that leg or foot, you would likely hop on one foot to get to the destination.)</em>

6 0
3 years ago
A wall, acted upon by a force of 20 N, does not move. The work done on the wall in this process is
jenyasd209 [6]

Answer:

0 (Zero)

Explanation:

Definition of work done states that ,

Work done on an object is the force applied on that object in the direction of Displacement of the object .

means that ,

W = F.dS (Dot product of Force and displacement)

When the wall is acted upon by the force of 20 N , Wall does not move ,

Thus , displacement of the wall is zero.

So, W = 20×0 = 0.

Thus, Work done on the wall is zero.

8 0
3 years ago
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