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Harman [31]
3 years ago
9

A high jumper jumps over a bar that is 2 m above the mat. With what velocity does the jumper strike the mat in the landing area?

(Disregard air resistance. g = 9.81 m/s2.)
Physics
1 answer:
docker41 [41]3 years ago
8 0

Answer:

The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.

Explanation:

It is given that,

A high jumper jumps over a bar that is 2 m above the mat, h = 2 m

We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :

v=\sqrt{2gh}

g is acceleration due to gravity

v=\sqrt{2\times 9.81\ m/s^2\times 2\ m}

v = 6.26 m/s

So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.

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Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the a
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The angular acceleration of the pencil<em> α  = 17 rad·s⁻²</em>

Explanation:

Using Newton's second angular law or torque to find angular acceleration, we get the following expressions:

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    W r = I α                          (2)

The weight is that the pencil has is,

   sin 10 = r / (L/2)

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The shape of the pencil can be approximated to be a cylinder that rotates on one end and therefore its moment of inertia will be:

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