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4 years ago

Nitrogen oxides and sulfur oxides make _____. acid rain ozone CFCs hydrocarbons

Chemistry

2 answers:

Finger [1]4 years ago

4 0

Answer: Option (a) is the correct answer.

Explanation:

Nitrogen oxide and sulfur dioxide released into the air results in the formation of acid rain.

This is because both nitrogen oxide and sulfur oxide are able to rise high into the atmosphere. These oxides mix and react with water, oxygen and other chemicals and thus it forms more acidic pollutants which are known as acid.

Thus, we can conclude that nitrogen oxides and sulfur oxides make acid rain.

vova2212 [387]4 years ago

3 0

I reckon it would be acid rain

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3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

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Answer: The mass of lead iodide produced is 9.22 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

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$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

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3 years ago

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