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Sidana [21]
3 years ago
9

If an astronaut has a mass of 80kg on earth, what is their mass on the moon?

Physics
1 answer:
stealth61 [152]3 years ago
6 0

Answer:

130 N basically

Explanation:

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C = 4 \ \mu F = 4 \cdot 10^{-6} \ F. \newline
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An electron is released from rest on the axis of a uniform positively charged ring, 0.200 m from the ring's center. If the linea
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Answer:

Velocity of the electron at the centre of the ring, v=1.37\times10^7\ \rm m/s

Explanation:

<u>Given:</u>

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Q=0.1\times2\pi R\\Q=0.1\times2\pi 0.4\\Q=0.251\ \rm \mu C

Potential due the ring at a distance x from the centre of the rings is given by

V=\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\

The potential difference when the electron moves from x=0.2 m to the centre of the ring is given by

\Delta V=\dfrac{kQ}{R}-\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\\Delta V={9\times10^9\times0.251\times10^{-6}} \left( \dfrac{1}{0.4}-\dfrac{1}{\sqrt{(0.4^2+0.2^2)}} \right )\\\Delta V=5.12\times10^2\ \rm V

Let\Delta U be the change in potential Energy given by

\Delta U=e\times \Delta V\\\Delta U=1.67\times10^{-19}\times5.12\times10^{2}\\\Delta U=8.55\times10^{-17}\ \rm J

Change in Potential Energy of the electron will be equal to the change in kinetic Energy of the electron

\Delta U=\dfrac{mv^2}{2}\\8.55\times10^{-17}=\dfrac{9.1\times10^{-31}v^2}{2}\\v=1.37\times10^7\ \rm m/s

So the electron will be moving with v=1.37\times10^7\ \rm m/s

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Two bicyclists are accelerating forward in a straight line, and Biker 1 has less mass than Biker 2. If the net force on the bike
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If  Biker 1 has less mass than Biker 2 it the follows that biker 1 has a greater acceleration than Biker 2.​

<h3>What is the Newton second law?</h3>

The Newton second law gives the relationship between the force and the acceleration. We know that; acceleration = Force/mass.

Now if Biker 1 has less mass than Biker 2 it the follows that biker 1 has a greater acceleration than Biker 2.​

Learn more about Newton's law:brainly.com/question/27573481

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