If an astronaut has a mass of 80kg on earth, what is their mass on the moon?

How long does it take for sound to travel 28 miles

rewona [7]

Answer:

i think near like 8 seconds i might be wrong

Explanation:

3 0

3 years ago

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Object 1 has a mass of 99.2 kg. Object 2 has a mass of 42.3 kg. If the 2 object pust against each other, what will be the speed

Vlad1618 [11]

Djdjkesbbdjsjsjsjssjsjks

7 0

3 years ago

A ball is thrown straight down with a velocity of 12 m/s; what will be its velocity 2.0 s after being released?

hichkok12 [17]

Answer:

$v = 31.6m/s$

Explanation:

Given

$Initial\ Velocity, u = 12m/s$

$Time, t = 2.0s$

Required

Determine the final velocity, v

Using the first equation of motion

$v = u + at$

But in this case;

a = g = acceleration of gravity

So:

$v = u + gt$

Substitute values for u and t

$v = 12 + g * 2$

$v = 12 + 2g$

Take g as 9.8m/s²

$v = 12 + 2 * 9.8$

$v = 12 + 19.6$

$v = 31.6m/s$

<em>Hence, the velocity is 31.6m/s</em>

3 0

4 years ago

A 750 Watt hairdryer is used for 15 minutes. Calculate the Kwhr used. Calculate the cost to use 15 min. every day for 1 year @ 8

Rufina [12.5K]

Part (a):
We know that:
1 kw = 1000 watt ..........> Therefore, to convert watt into kw, we will divide by 1000
1 hour = 60 min ..........> Therefore, to convert mins into hours, we will divide by 60
Based on the above, the conversion results for the two units together would be as follows:
1 watt minute is equivalent to <span>0.000017 kilowatt hours
</span>Now, for the given , we will simply use cross multiplication to do the conversion as follows:
1 watt minute..............> 0.000017 kilowatt hours
750*15 ................> ??
750*15 watt min = 0.19125 kilowatt hour

Part (b):
From part a, we have that the consumption is 0.19125 kilowatt hour per day. Assuming that the year is 365 days, we would have:
yearly consumption = 0.19125 * 365 = 69.80625 kilowatt hour
The cost is 8 cents/kilowatt hour
Therefore:
yearly cost = 69.80625 * 8 = 558.45 cents

Hope this helps :)

8 0

3 years ago

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Imagine that I have a ping-pong ball and a bowling ball resting on the floor of our classroom. I go up to the bowling ball and g

MatroZZZ [7]

Answer:

the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Explanation:

We can analyze this exercise from several points of view, if we use Newton's second law

Bowling ball

F = M a₁

pingpongg ball

F = m a₂

as the forces the same

M a₁ = m a₂

a₂ = $\frac{M}{m}$ a₁

Since the mass of the bowling ball is much greater than the ping pong ball,

a₂ »a₁

so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.

If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest

Bowling ball

I = F t = Δp

I = M (v₁ - v₀)

Ping pong ball

I = F t = Δp

I = m (v₂ -v₀)

the impulse itself

M v₁ = m v₂

v₂ = $\frac{M }{ m}$ v₁

so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.

In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

4 0

3 years ago