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Liono4ka [1.6K]
3 years ago
15

The molecules in this substance are packed tightly and vibrating. The substance might be

Physics
2 answers:
Fittoniya [83]3 years ago
8 0
The substance would be a solid because the particles are packed tightly and vibrating.
azamat3 years ago
4 0
A Solid? Because its a substance tightly packed together. 
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What cultular value does this melodic line portray?<br>a.jubilant<br>b.reserved<br>c.rich<br>d.poor​
SOVA2 [1]

<em>What cultular value does this melodic line portray?</em>

<em>answer</em><em> </em><em>:</em><em> </em><em>reserved</em><em>.</em><em>.</em><em>.</em>

6 0
3 years ago
A turntable that spins at a constant 80.0 rpmrpm takes 3.50 ss to reach this angular speed after it is turned on. Find its angul
Veronika [31]

Answer:

The angular acceleration is <u>2.39 rad/s²</u>.

The number of degrees it rotates is <u>841.68 degrees</u>.

Explanation:

Given:

Initial angular speed (ω₀) = 0 rad/s

Final angular speed in rpm (N) = 80.0 rpm

Time taken (t) = 3.50 s

First, let us determine the final angular speed in radians per second.

We know that,

\omega=\frac{2\pi N}{60}\ rad/s

Plug in the values and find the final angular speed, 'ω'. This gives,

\omega=\frac{2\pi\times 80.0}{60}=8.38\ rad/s

Now, using equation of motion for rotational motion, we have:

\omega=\omega_0+\alpha t\\\\\alpha\to angular\ acceleration

Plug in the given values and solve for α. This gives,

8.38=0+\alpha \times 3.50\\\\\alpha=\frac{8.38}{3.50}=2.39\ rad/s^2

Therefore, the angular acceleration is 2.39 rad/s².

Now, again using rotational equation of motion relating angular displacement, we have:

\omega^2=\omega_0^2+2\alpha\theta\\\\\theta=\frac{\omega^2-\omega_0^2}{2\alpha }

Plug in the given values and solve for 'θ'. This gives,

\theta=\frac{(8.38)^2-0}{2\times 2.39}\\\\\theta=\frac{70.2244}{4.78}=14.69\ rad

Convert radians to degrees using the conversion factor. This gives,

π radians = 180°

So, 1 radian =( 180 ÷ π ) degrees

Therefore, 14.69\ rad=14.69\times (\frac{180}{\pi})=841.68^\circ

So, the number of degrees it rotates is 841.68 degrees.

3 0
3 years ago
48 grams 12cm^3, what would the density of the material be
Licemer1 [7]
Density is mass over volume:

D =  \frac{m}{V}

In your case, mass is 48 grams and volume is 12cm^3

If you put that into the equation, you will get your density:

D =  \frac{m}{V} =  \frac{48g}{12cm^{3} } =4g/ cm^{3}
7 0
4 years ago
A stone of mass m = 1.05 kg is released from a height of h = 2.1 m into a pool of water. At a time of t = 1.83 s after hitting t
mote1985 [20]

Answer:

Explanation:

ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted

½mv² = mgh

v = √(2gh)

v = √(2(9.81)2.1) = 6.4188... m/s

after impact, an impulse will result in a change of momentum.

There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.

FΔt = mΔv

(F - mg)Δt = m(vf - vi)

(F - mg) = m(vf - vi)/Δt

F = m(vf - vi)/Δt + mg

F = m((vf - vi)/Δt + g)

F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)

F = 12.14198...

F = 12.1 N

7 0
2 years ago
A 10-kg rock falls from a height of 8-m above the ground. What is the kinetic energy of the rock just before it hits the ground?
pishuonlain [190]

Answer: 800

Explanation:

1/2 x m x v^2 = m x g x h

KE = 10 x 10 x 8

KE= 800

3 0
3 years ago
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