Answer:
90 meters
Explanation:
To find the distance in which Bob catches up with Wendy, you first write down the motion equations of both Bob and Wendy.
Wendy has a constant speed, then you have:
(1)
Bob has an accelerated motion, then, his equation of motion is:
(2)
v1: constant speed of Wendy = 3.00 m/s
v2: initial speed of Bob = 0 m/s
a: acceleration of Bob = 0.200m/s^2
When Bob catches up with Wendy x1 = x2, then you equal both equations and solve for time t:

you replace the values of a and v1:

Finally, you replace this value of time either the equation for x1 or the equation for x2, and you calculate the distance:

hence, Bob catches up with Wendy for a distance of 90m