Question

Uranium-235 decays naturally, by alpha decay. Write the balance decay equation below

Answer 1

Answer

92U^235→90Th^231+2He^4

Explanation

Uranium-235 produces thorium-231 by alpha decay.

An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.

During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.

Thus, uranium-238 decays through α-particle emission to form thorium-231  

92U^235  → 90Th^231  + 2He^4

Answer 2

If all you are getting is Th then the balanced equation is written below

$_{92}^{235}\text{U} \longrightarrow _{90}^{231}\text{Th +}_{2}^{4}\text{He}$

The Uranium 235 decays into Thorium 231 and an alpha particle.

I'm not sure this decay happens in nature, but Uranium 238 does decay this way.