Answer:
the width of the turning roadway = 15 ft
Explanation:
Given that:
A ramp from an expressway with a design speed(u) = 30 mi/h connects with a local road
Using 0.08 for superelevation(e)
The minimum radius of the curve on the road can be determined by using the expression:

where;
R= radius
= coefficient of friction
From the tables of coefficient of friction for a design speed at 30 mi/h ;
= 0.20
So;



R = 214.29 ft
R ≅ 215 ft
However; given that :
The turning roadway has stabilized shoulders on both sides and will provide for a onelane, one-way operation with no provision for passing a stalled vehicle.
From the tables of "Design widths of pavement for turning roads"
For a One-way operation with no provision for passing a stalled vehicle; this criteria falls under Case 1 operation
Similarly; we are told that the design vehicle is a single-unit truck; so therefore , it falls under traffic condition B.
As such in Case 1 operation that falls under traffic condition B in accordance with the Design widths of pavement for turning roads;
If the radius = 215 ft; the value for the width of the turning roadway for this conditions = 15ft
Hence; the width of the turning roadway = 15 ft
Answer:
domestic, public, commercial, and industrial uses.
Answer:
The minimum diameter is 1.344 in
Explanation:
The angular speed of the driveshaft is equal to:

Where
N = rotational speed of the driveshaft = 2900 rpm

The torque in the driveshaft is equal to:

Where
P = power transmitted by the driveshaft = 134 hp = 73700 lb*ft/s

The minimum diameter is equal to:

Where
T = shear stress = 6100 psi
τ = 242.68 lb*ft = 2912.16 lb*in

Answer:
I dont know sorry i in a hurry and i need points so vary sorry
Explanation:
my assistant is due at 9:00 today . Not that you care but