Answer:
Part A:
Part B:
Part C:
Explanation:
Part A:
We will use the following kinematics equation:
Part B:
We will use the same kinematics equation:
Part C:
The total time takes is 2t.
So the train moves a distance of
And the car moves a distance in Part A and in Part B:
So the total distance that the car traveled is
The difference between the train and the car is
Answer:
The input force is the force that when you push down and the output force is the stable going into the paper.
Explanation:
I really hope this helps ;)
Http://www.kyrene.org/cms/lib2/AZ01001083/Centricity/Domain/2932/Peppered%20Moth%20and%20Galapados%20Island%20PowerPoint.pptx
This should lead you to correct answer
Explanation:
have similar chemical properties
Answer:
The question implies that force of friction is 2.1E4 N
F = M v^2 / R frictional force needed to supply this centripetal force
2.1E4 = M v^2 / R
v^2 = R * 2.1E4 / M
v^2 = 120 * 2.1E4 / 2.5E3 = 1200 * 2.1 / 2.5 = 1008 m^2/s^2
v = 31.7 m/s max speed of truck (about 70 MPH)