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Oliga [24]
3 years ago
14

If I now have 3g of Iodine-131, how much did I have 16 days ago?

Physics
1 answer:
qaws [65]3 years ago
7 0

Answer:

12 grams of Iodine-13 was present 16 days ago

Explanation:

Given:

Amount of  Iodine-131 sample present now  = 3g

To Find:

Amount of Iodine-131 sample present before 16 days = ?

Solution:

W know that the half life of  Iodine-131  is  8days

Let the amount of sample before 16 days be X

Then

The  X amount  Iodine-131 sample will decay ito ist half after 8 days

after 8 days

=> X \times \frac{1}{2}

=> \frac{X}{2}

after  next 8 days , i.e., 16 days

=> \frac{X}{2}\times \frac{1}{2}

=> \frac{X}{4}

Now we know that after 16 days we have 3 grams of Iodine-131 sample

So,

\frac{X}{4}  = 3

X = 4 \times 3

X = 12

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Answer:

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Explanation:

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What are the SI units of thermal conductivity?​
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The action of property being taken directly from a person or in that person's presence must be an element in which type of crime
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3 years ago
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An elevator cable breaks when a 925-kg elevator is 28.5 m above the top of a huge spring Ak = 8.00 * 104 N????mB at the bottom o
rosijanka [135]

Answer:

a) = 258352.5J

b) = 23.63 m/s

c) = 1.8m

Explanation:

Data;

Mass = 925kg

Distance (s) = 28.5m

Force constant (k) = 8.0*10⁴ N/m

g = 9.8 m/s²

a) = work = force * distance

But force = mass * acceleration

Force = 925 * 9.8 = 9065N

Work = F * s = 9065 * 28.5 = 258352.5J

b) acceleration (a) = (v² - u²) / 2s

a = v² / 2s

v² = a * 2s

v² = 9.8 * (2 * 28.5)

v² = 9.8 * 57

v² = 558.6

v = √(558.6)

V = 23.63 m/s

C). The work stops when the work done to raise the spring equals the work done to stop it by the spring

W = ½kx²

258352.5 = ½ * 8.0*10⁴ * x²

(2 * 258352.5) = 8.0*10⁴x²

516705 = 8.0*10⁴x²

X² = 516705 / 8.0*10⁴

X² = 6.46

X = √(6.46)

X = 2.54m

The compression was about 2.54m

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3 years ago
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