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olya-2409 [2.1K]
3 years ago
12

Sample of gas initially occupies 4.25 L at a pressure of 0.850 atm at 23.0°C. What will the volume be if the temperature is chan

ged to 11.5°C, and the pressure is changed to 1.50 atm?
Chemistry
1 answer:
Aliun [14]3 years ago
3 0

Answer:  2.34 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.850 atm

P_2 = final pressure of gas = 1.50 atm

V_1 = initial volume of gas = 4.25 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 23.0^oC=273+23.0=293.0K

T_2 = final temperature of gas = 11.5^oC=273+11.5=284.5K

Now put all the given values in the above equation, we get:

\frac{0.850\times 4.25}{293.0K}=\frac{1.50\times V_2}{284.5}

V_2=2.34L

Thus the final volume will be 2.34 L

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