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ale4655 [162]
3 years ago
15

You are working on charge-storage devices for a research center. Your goal is to store as much charge on a given device as possi

ble. The facilities allow you to generate almost any potential difference V you need, but you are restricted to using a single parallel-plate capacitor. The area and separation distance of the plates are fixed, and the dielectric materials available to you are paper (κ = 3.0, Emax=4.0×107V/m), Mylar (κ = 3.3, Emax=4.3×108V/m), quartz (κ = 4.3, Emax=8×106V/m), and mica (κ = 5, Emax=2×108V/m).
Part A. What properties of these materials must you consider in choosing the best dielectric for your needs? Check all that apply.
a. mass density
b. dielectric constant breakdown threshold
c. electric conductivity
Part B. Rank the materials in order of their ability to meet your needs, first choice first. Rank the materials from the most appropriate to the least appropriate. To rank items as equivalent, overlap them. HelpReset paperquartzmicaMylar Least appropriateMost appropriate The correct ranking cannot be determined.
Physics
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer:

Part A the answer is the dielectric constant.

Part B  Mica- mylar- paper- quartz

Explanation:

The capacity of a capacitor is given by

           C = ε ε₀ A / d

Where the dielectric constant (ε) is the value of the material between the plates of the capacitor, we see that as if value increases the capacity also increases.

Another magnitude that we must take into account that the maximum working voltage, the greater the safer is the capacitor

the flexibility of the material must also be taken into account

Part A the answer is the dielectric constant.

Pate B order the materials from best to worst

Mica. The best ever

Mylar Flexible

Paper Low capacity, low working voltage, flexible

Quartz high dielectric, but brittle

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saul85 [17]

<u>We are given:</u>

Mass of Neptune = 1.03 * 10²⁶ kg

Distance from the center of Neptune (r) = 2.27 * 10⁷

now, computing the value of the acceleration due to gravity (g)

<u>Finding g:</u>

We know the formula:

g = G(mass of planet) / (r)²

g = [6.67 * 10⁻¹¹ * 1.03*10²⁶] / (2.27*10⁷)                      [since G is 6.67*10⁻¹¹]

g = (6.87 * 10¹⁵) / (5.15 * 10¹⁴)

which can be rewritten as:

g = (6.87 * 10¹⁵ * 10⁻¹⁴) / 5.15

g = (6.87 * 10¹⁵⁻¹⁴) / 5.15

g = (6.87/5.15) * 10

g = 1.34 * 10

g = 13.4 m/s² <em>(approx)</em>

5 0
3 years ago
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Alchen [17]

Answer:

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7 0
3 years ago
What everyday things exist bc of science?
fredd [130]
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6 0
3 years ago
In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. Calculate the ma
Mrac [35]

Answer:

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3 years ago
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Veseljchak [2.6K]

Answer:

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