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umka21 [38]
3 years ago
12

The intensity of most of the cyclonic storm reduces after hitting land. Explain giving suitable reasons.

Physics
2 answers:
Alja [10]3 years ago
7 0

The intensity of most of the cyclonic storm reduces after hitting land due to the transfer of storm energy to the land because of friction between them and also as the shortage of moisture in land.

Explanation:

The cyclonic storm has very high speed and also lot of moisture content is present in the cyclonic storms as they are formed from interior of ocean.

The cyclonic storms originate by getting energy from the warm tropical oceans and in open space.

The storm originating region should have constant temperature of about 26.5 °C.

So when these storms with high moisture content and temperature reaches the land, the objects in land like houses, trees, bushes, vehicles and many more hinders the movement of the storm, thus transferring the storm energy to destroy them on the path of storm.

This causes a frictional force which leads to some loss in the storm strength and the other factor is the difference between the temperature gradient of land compared to sea level and the absence of moisture in the land also leading to rain fall which in turn weakens the cyclonic storm.

yulyashka [42]3 years ago
5 0

The intensity of most cyclones reduces after hitting land because land takes away the heat and moisture of tropical ocean water. In order to survive, cyclone storms need evaporation from the warm sea surface. Intensity also decreases because of greater fiction on land, compared to the sea surface.

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A 5,400 W motor is used to do work. If the motor is used for 640 s, about how much work could it do?
Gemiola [76]

Answer:

3,500,000 J​

Explanation:

WORK = POWER * TIME

WORK= 5400 * 640

=6456000 J = 3,500,000 J​

4 0
3 years ago
A ball is shot straight up into the air from the ground with initial velocity of 44ft/sec44ft/sec. assuming that the air resista
solniwko [45]
Convert the given in SI units.

         (44 ft/sec)(1 m/ 3.28 ft) = 13.41 m/sec

The distance traveled and the initial velocity can be related through the equation,
  
   d = (Vf)² - (Vi)²/ 2a

where d is the distance, Vf is the final velocity, Vi is the initial velocity, a is the acceleration due to gravity. Substituting the known values from the given above,

    d = ((0 m/s)² - (13.41 m/s)²)/ 2(-9.8 m/s²)

The value of d from the equation,

    d = 9.17 meters

Convert this to feet,

    d = (9.17 m)(3.28 ft / 1 m) = 30 ft

Answer: 30 ft
3 0
3 years ago
a bus starting from rest moves with a uniform acceleration of 0.1 metre per second square for 2 minutes find the speed acquired
blondinia [14]
S ?
U 0m/s
V ?
A 0.1m/s^2
T 2min (120 sec)

S=ut+0.5at^2
S=0(120 sec)+0.5(0.1m/s^2)(120 sec)^2
S=720m

Distance double 720m*2=1440m

V^2=u^2+2as
V^2=(0)^2+2(0.1 m/s^2)(1440m)
V^2=288
V= square root of 288=12 root 2=16.97 to 2 decimal places
6 0
3 years ago
When a object slows down what direction is the force going?
trapecia [35]

Answer: when a object gets slowed down, it's force is either going into friction and drag, if it's on the ground, and weight+drag+friction, if it's in the air.

Explanation:

7 0
3 years ago
PLEASE HELP!
Anna [14]

Answer:

Explanation:

At constant pressure , work done by gas = P x ΔV where P is pressure and ΔV is change in volume

ΔV = 9.2 - 5.6 = 3.6 L

3.6 L = 3.6 x 10⁻³ m³

ΔV = 3.6 x 10⁻³ m³

P = 3.7 x 10³ Pa

So work done

= 3.7 x 10³ x 3.6 x 10⁻³ J

= 13.32 J .

( c ) is the answer , because work is done by the gas so it will be positive.

5 0
3 years ago
Read 2 more answers
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