The intensity of most of the cyclonic storm reduces after hitting land. Explain giving suitable reasons.

2 answers:

7 0

The intensity of most of the cyclonic storm reduces after hitting land due to the transfer of storm energy to the land because of friction between them and also as the shortage of moisture in land.

Explanation:

The cyclonic storm has very high speed and also lot of moisture content is present in the cyclonic storms as they are formed from interior of ocean.

The cyclonic storms originate by getting energy from the warm tropical oceans and in open space.

The storm originating region should have constant temperature of about 26.5 °C.

So when these storms with high moisture content and temperature reaches the land, the objects in land like houses, trees, bushes, vehicles and many more hinders the movement of the storm, thus transferring the storm energy to destroy them on the path of storm.

This causes a frictional force which leads to some loss in the storm strength and the other factor is the difference between the temperature gradient of land compared to sea level and the absence of moisture in the land also leading to rain fall which in turn weakens the cyclonic storm.

yulyashka [42]2 years ago

5 0

The intensity of most cyclones reduces after hitting land because land takes away the heat and moisture of tropical ocean water. In order to survive, cyclone storms need evaporation from the warm sea surface. Intensity also decreases because of greater fiction on land, compared to the sea surface.

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Svetradugi [14.3K]

Answer:

Explanation:

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The correct option is A.

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2 years ago

A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction,

Romashka [77]

Answer:

$v_{y} = -104 m/s$

Explanation:

Using:

Force = electric field * charge

$F=e*q$

Force = magnitude of charge * velocity * magnetic field * sin tither

$F_{x2}= |q|*v*B*sin \alpha$

Force on particle due to electric field:

$F_{x1}= E*q = (1270N/C)*(-6.72*10^{-6} ) = -8.53*10^{-3}$

Force on particle due to magnetic field:

$F_{x2}= |q|*v*B*sin \alpha = (6.72*10^{-6} )*(1.15)*(sin90)*v = (7.728*10^{-6})*(v)$

$F_{x2}$ is in the positive x direction as $F_{x1}$ is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

$F_{xnet}- F_{x1 } = F_{x2 }$