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3 years ago

Which term describes a rock that formed from cooling molten rock?

Physics

2 answers:

Talja [164]3 years ago

7 0

I thinks it Igneous Rocks?!

Sedbober [7]3 years ago

5 0

Material called magma is formed deep withing the Earth. lava (magma that reaches the surface) cools and hardens at the Earth's surface. this region contains igneous rocks or metamorphic rocks.

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The small intestine _____.

VladimirAG [237]

Answer:

the small intestine digest food

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3 years ago

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List 3 quantities of waves.

VARVARA [1.3K]

If you mean like electromagnetic waves then, Mico waves, UV rays, and infrared waves

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4 years ago

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The electric field between the plates of a parallel-plate capacitor is horizontal, uniform, and has a magnitude E. Asmall object

kirza4 [7]

Answer:

$m = 0.041 kg$

Explanation:

As we know that the small particle is in equilibrium at an angle of 16 degree with the vertical

so here we can use force balance in vertical and horizontal direction

$T cos\theta = mg$

$T sin\theta = qE$

now from above equation we have

$T = \sqrt{(mg)^2 + (qE)^2}$

also by division of above two equations we have

$\frac{qE}{mg} = tan\theta$

$qE = mg tan\theta$

now from above equation again

$T = \sqrt{(mg)^2 + (mg)^2 tan^2\theta}$

$T = mg sec\theta$

$0.420 = m(9.81) sec 16$

$m = 0.041 kg$

3 0

3 years ago

Give the reason of evidence and claim.

Sliva [168]

Answer:

it shows a black screen

Explanation:

6 0

3 years ago

An electron has a velocity of 1.50 km/s (in the positive x direction) and an acceleration of 2.00 ✕ 1012 m/s2 (in the positive z

olga nikolaevna [1]

Answer:

see explanation

Explanation:

Given that,

velocity of 1.50 km/s = 1.50 × 10³m/s

acceleration of 2.00 ✕ 1012 m/s2

electric field has a magnitude of strength of 18.0 N/C

$\bar F= q[\bar E + \bar V \times \bar B]\\\\\bar F = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]\\\\\\m \bar a = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]$

$9.1 \times 10^-^3^1 \times 2\times 10^1^2 \hat k=-1.6\times10^-^1^9 \hat k [18\hat k+ 1.5\times 10^3 \hat i \times (B_x \hat i +B_y \hat j +B_z \hat k)]$ $42.2 \times 10^-^1^9 \hat k = -2.4 \times 10^1^6B_y \hat k + 2.4 \times 10 ^1^6 \hat j B_z\\$

$B_x = undetermined$

$B_y = \frac{42.2 \times 10^-^1^9}{-2.4 \times 10^-^1^6} \\\\= - 0.0176 T$

$B_z = 0T$

8 0

4 years ago